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bulgar [2K]
2 years ago
7

A 16-cm-diameter circular loop of wire is placed in a 0.64-t magnetic field. part a when the plane of the loop is perpendicular

to the field lines, what is the magnetic flux through the loop?
Physics
1 answer:
aleksley [76]2 years ago
6 0

128.72 Wb is the magnetic flux through the loop.

<h3>What is magnetic flux?</h3>

Attractive motion is an actual amount that addresses the circulation of an attractive field and is a scalar amount. In the event that there are two attractive motions in inverse headings across a plane, the attractive transition in the plane is the logarithmic amount of the attractive motions the other way. This attraction's solidarity is actually known as attractive motion thickness, and is straightforwardly corresponding to the electric flow size or strength. In any case, attractive transition doesn't really move from the north toward the south pole or stream anyplace so far as that is concerned as attractive motion is a static district around a magnet wherein the attractive power exists.

Learn more about magnetic flux, visit

brainly.com/question/23009557

#SPJ4

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On a frozen pond, a 10.3 kg sled is given a kick that imparts to it an initial speed of vo = 1.64 m/s. The coefficient of kineti
alukav5142 [94]

Answer:

d=1.07m

Explanation:

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KE = 1/2*m*v^2

KE= 0.5*(10.3kg)*(1.64m/s)^2 = 13.85J

Calculate work overcoming friction:

W = F*d = mu*m*g*d

W = (0.128)*(10.3kg)*9.80m/s^2)*d

W = 12.92*d

Equate the two since all of the kinetic energy is used up in working against friction:

W = KE

12.92d = 13.851J

Solve for d:

d= (13.851J)/(12.92) = 1.07 m

5 0
4 years ago
78. A film of oil on water will appear dark when it is very thin, because the path length difference becomes small compared with
Hoochie [10]

To solve this problem it is necessary to apply the concepts related to the condition of path difference for destructive interference between the two reflected waves from the top and bottom of a surface.

Mathematically this expression can be described under the equation

\delta = 2nt

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t = Thickness

In terms of the wavelength the path difference of the reflected waves can be described as

\delta = \frac{\lambda}{4}

Where

\lambda = Wavelenght

Equation the two equations we have that

2nt = \frac{\lambda}{4}

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4 0
3 years ago
The average marathon runner can complete the 42.2-km distance of the marathon in 3 h and 30 min. If the runner's mass is 85 kg,
Semenov [28]

Answer:

the runner's average kinetic energy during the run is 476.96 J.

Explanation:

Given;

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distance covered by the runner, d = 42.2 km = 42,200 m

time to complete the race, t = 3 hours 30 mins = (3 x 3600s) + (30 x 60s)

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The speed of the runner, v = d/t

                                          v = 42,200 / 12,600

                                          v = 3.35 m/s

The runner's average kinetic energy during the run is calculated as;

K.E = ¹/₂mv²

K.E = ¹/₂ × 85 × (3.35)²

K.E = 476.96 J

Therefore, the runner's average kinetic energy during the run is 476.96 J.

5 0
3 years ago
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Oksana_A [137]

Answer:

When the temperature of the coffee is 50 °C, the time will be 20.68 mins

Explanation:

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\frac{dT}{dt} \alpha (T-21)\\\\\frac{dT}{dt} = k (T-21)\\\\\frac{dT}{T-21} = kdt\\\\\int\limits {\frac{dT}{T-21}}  =  \int\limits kdt\\\\Log(T-21) =kt +  Logc \\\\Log (\frac{T-21}{c} ) = kt\\\\T -21 = ce^{kt}\\\\At \ t = 0, T = 95\\\\95-21 = ce^0\\\\74 = c\\\\New, equation: T -21 = 74e^{kt}\\\\Again; when \ t= 5\ min, T = 80\\\\80 -21 = 74e^{5k}\\\\59 = 74e^{5k}\\\\e^{5k} = \frac{59}{74}\\\\ 5k = ln(\frac{59}{74})\\\\5k = -0.2265\\\\k = -0.0453

When the temperature is 50 °C, the time t in min is calculated as;

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Therefore, when the temperature of the coffee is 50 °C, the time will be 20.68 mins

4 0
3 years ago
The container is filled to yh 350 ml mark water is observation or inference?
Lorico [155]
This is an observation.
4 0
4 years ago
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