Answer:
Final temperature, ![T_f=21.85^{\circ}](https://tex.z-dn.net/?f=T_f%3D21.85%5E%7B%5Ccirc%7D)
Explanation:
Given that,
Mass of silver ring, m = 4 g
Initial temperature, ![T_i=41^{\circ}C](https://tex.z-dn.net/?f=T_i%3D41%5E%7B%5Ccirc%7DC)
Heat released, Q = -18 J (as heat is released)
Specific heat capacity of silver, ![c=0.235\ J/g\ C](https://tex.z-dn.net/?f=c%3D0.235%5C%20J%2Fg%5C%20C)
To find,
Final temperature
Solution,
The expression for the specific heat is given by :
![Q=mc\Delta T](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20T)
![Q=mc(T_f-T_i)](https://tex.z-dn.net/?f=Q%3Dmc%28T_f-T_i%29)
![T_f=\dfrac{-Q}{mc}+T_i](https://tex.z-dn.net/?f=T_f%3D%5Cdfrac%7B-Q%7D%7Bmc%7D%2BT_i)
![T_f=\dfrac{-18}{4\times 0.235}+41](https://tex.z-dn.net/?f=T_f%3D%5Cdfrac%7B-18%7D%7B4%5Ctimes%200.235%7D%2B41)
![T_f=21.85^{\circ}](https://tex.z-dn.net/?f=T_f%3D21.85%5E%7B%5Ccirc%7D)
So, the final temperature of silver is 21.85 degrees Celsius.
Answer:
force for start moving is 7.49 N
force for moving constant velocity 2.25 N
Explanation:
given data
mass = 7.65 kg
kinetic coefficient of friction = 0.030
static coefficient of friction = 0.10
solution
we get here first weight of block of ice that is
weight of block of ice = mass × g
weight of block of ice = 7.65 × 9.8 = 74.97 N
so here Ff = Fa
so for force for start moving is
Fa = weight × static coefficient of friction
Fa = 74.97 × 0.10
Fa = 7.49 N
and
force for moving constant velocity is
Fa = weight × kinetic coefficient of friction
Fa = 74.97 × 0.030
Fa = 2.25 N
Sodium and potassium are positively charged ions called cations, and chloride and phosphate form negatively charged ions called anions. is true!