Answer:
Explanation:
Theoretical efficiency = T₁ - T₂ / T₁ where T₁ and T₂ is absolute temperature of hot and cold end of the heat engine.
= 600 / (273 + 700 )
= 600 / 973
= .6166
operating efficiency = 40% of .6166
= .4 x .6166
= .2466 = 24.66 %
efficiency = work output / heat input
= 5000 / heat input = .2466
heat input = 5000 / .2466
= 20275.75 J .
HEAT EXTRACED = 20275.75 J.
The correct answer is: +5
Explanation:
An object is placed at 0; it means:
Initial position of the object = 0.
Now it moves to 3 units to right, so keeping the standard cartesian coordinate system in mind (in right right x-axis is positive and left x-axis is right), the new position of the object will be +3.
Object now moves 4 units to the left, it means +3 - 4 = -1; object is at the position -1.
Object then moves 6 units to the right, therefore,
Final position of the object = -1 + 6 = +5.
Displacement = Final position - Initial position
Displacement = +5 - 0 = +5
Answer:
Law of refraction
Explanation:
An experiment to analyze the refraction of light in water can easily be performed with a laser pointer and protractor.
We throw the fishing rod line into the water, place the protractor at the point where the line touches the water and use the direction of the line for the direction of the laser pointer (on), the laser is visible by the reflection on the particles in the air.
The vertical line is called Normal and all angles must be measured with respect to this reference in optics.
Having these angles and the refractive index of water we can use the law of refraction
n₁ sin θ₁ = n₂ sin θ₂
θ₂ =
we can repeat several times to analyze several different input points (different angles) and to decrease the errors in the measurements.
the refractive index of air is n1 = 1 and n2= 1.33 (water)
Answer:
The total elongation for the tension member is of 0.25mm
Explanation:
Assuming that material is under a linear deformation then the relation between the stress and the specific elongation is given as:
(1)
Where E is the modulus of elasticity, σ the stress and ε the specific deformation. Also, the total longitudinal elongation can be expressed as:
(2)
Here L is the member extension and δL the change total longitudinal elongation.
Now if the stress is found then the deformation can be calculated by solving the stress-deformation equation (1). The stress applied sigama is computed dividing the axial load P by the cross-sectional area A:
Solving for epsilon and replacing the calculated value for the stress and the value for the modulus of elasticity:




Finally introducing the specific deformation and the longitudinal extension in the equation of total elongation (2):
Multiplying the ideal gas law constant