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LenKa [72]
4 years ago
13

I throw a 1 kg rock at 5 m/s. How much energy does it have?

Physics
1 answer:
VashaNatasha [74]4 years ago
4 0

Answer:

KE = 12.5 J

Explanation:

Where:

KE=1/2mv^2

KE = kinetic energy

m = mass of a body

v = velocity of a body

Kinetic Energy

Kinetic Energy is the energy an object has owing to its motion. In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

We use Joules, kilograms, and meters per second as our defaults, although any appropriate units for mass (grams, ounces, etc.) or velocity (miles per hour, millimeters per second, etc.) could certainly be used as well - the calculation is the same regardless.

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The last one, the soil will become weak & unable to support plant growth
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Is space expanding within clusters of galaxies? why or why not?
GarryVolchara [31]

No, since their gravity is powerful enough to keep them together even while the universe expands as a whole. Space is not expanding within clusters of galaxies.

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6 0
2 years ago
Resolving power of a telescope whose objective lens has diameter 1.22m for a wavelength 4000 Å.​
Mamont248 [21]

\sf \huge \purple{ Answer : - }

Diameter of objective lens = 1.22m

Wavelength of light = 4000Å

We have to find resolving power of telescope ..

★ Resolving power of telescope is given by

RP = D/1.22λ

  • D denotes diameter of lens
  • λ denotes wavelength of light

RP = D/1.22λ

RP = (1.22×10⁷)/(1.22×4)

RP = 0.25 × 10⁷

RP = 2.5 × 10⁶

★ Resolving power of microscope is given by

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5 0
3 years ago
Work is done if you carry a plant across a room at constant velocity. True False
BlackZzzverrR [31]

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5 0
4 years ago
Read 2 more answers
A child bounces a 51 g superball on the sidewalk. The velocity change of the super bowl is from 22 m/s downward to 14 m/s upward
noname [10]

Answer:

F=1.02x10^{-3} N

Explanation:

From the exercise we know:

m=51g*\frac{1kg}{1000g}=0.051kg

v_{1}=-22m/s

v_{2}=14m/s

t_{2}-t_{1}=1800s

So, the average acceleration is:

a=\frac{v_{2}-v_{1}}{t_{2}-t_{1}}=\frac{(14-(-22))m/s}{1800s}=0.02m/s^2

The average force is:

F=m*a=(0.051kg)(0.02m/s^2)=1.02x10^{-3} N

8 0
3 years ago
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