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AysviL [449]
4 years ago
8

Read the following characteristics of stars and choose the one that is correct. plz help quickly

Physics
1 answer:
aleksklad [387]4 years ago
4 0
The answer to this question will D
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Why is copper a good conductor?
IgorLugansk [536]
Copper conducts electricity
4 0
3 years ago
Read 2 more answers
Sandra's target heart rate zone is 135bpm—172bpm. Marissa's target heart rate zone is 143bpm—176bpm. They stop playing basketbal
Feliz [49]

Answer: Neither Sandra nor Marissa will be in her THR zone.


Explanation:


1) Actual pulse of both Sandra and Marissa : 144 bpm


2) Decrease of 20 bpm ⇒ 144 bpm - 20 bpm = 124 bpm


3) Sandra's TRH is in the range 135 - 172 bpm.


Since 124 < 135, she will be below the range.


4) Marissa's TRH range is 143 - 176 bpm.


Since, 124 < 143, she is below the range


In conlusion, neither Sandra nor Marissa will be in her THR zone.

6 0
3 years ago
Read 2 more answers
You measure the pressure of the four tires of your car each to be 35.0 pounds per square inch (psi). You then roll your car forw
Oksi-84 [34.3K]

Answer:

Weight of car = 36034.88 lb.ft/s²

Explanation:

We are told the pressure of the four tires of your car is; P = 35.0 psi

Also, the surface area of contact is; A = 32 in²

Thus;

Weight of tires = Pressure × Area

W_tires = 35 × 32

Weight_tires = 1120lb.

To get the weight of the car, we will multiply the tire weight by acceleration due to gravity.

It's value in ft/s² is g = 32.174 ft/s²

Thus;

Weight of car = 1120 × 32.174

Weight of car = 36034.88 lb.ft/s²

5 0
3 years ago
Calculate the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal. Assume that the spe
goblinko [34]

Answer:

the ratio of the kinetic energy of an electron to that of a proton if their wavelengths are equal is 1835.16 .

Explanation:

We know, wavelength is expressed in terms of Kinetic Energy by :

\lambda=\dfrac{h}{\sqrt{2mE}}

Therefore , E=\dfrac{h^2}{2 \lambda^2 m}

It is given that both electron and proton have same wavelength.

Therefore,

E_e=\dfrac{h^2}{2 \lambda^2 m_e}   .... equation 1.

E_p=\dfrac{h^2}{2 \lambda^2 m_p}   .... equation 2.

Now, dividing equation 1 by 2 .

We get ,

\dfrac{E_e}{E_p}=\dfrac{\dfrac{h^2}{2 \lambda^2 m_e}}{\dfrac{h^2}{2 \lambda^2 m_p}}\\\\\\\dfrac{E_e}{E_p}=\dfrac{m_p}{m_e}

Putting value of mass of electron = 9.1\times 10^{-31}\ kg and mass of proton = 1.67\times 10^{-27}\ kg.

We get :

\dfrac{E_e}{E_p}=\dfrac{1.67\times 10^{-27}\ kg}{9.1\times 10^{-31}\ kg}=1835.16

Hence , this is the required solution.

4 0
4 years ago
Read 2 more answers
Formulating an Investigative Question
valentina_108 [34]

Answer:

How do mass and speed affect kinetic energy?

Explanation:

This was edges sample resopnse so do not copy and just put this in your own words.

Have a great day whoever reads this.

8 0
3 years ago
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