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ladessa [460]
2 years ago
10

Cassini has a mass of 2523 kg, and Saturn

Chemistry
1 answer:
Amiraneli [1.4K]2 years ago
4 0

The F is 2.980 x 104 N  gravity Gm1 is  2523 kg m₂ is 5.68 x 1026 kg and radius 54,364 km and height is 108,728 km.

<h3>What is gravity?</h3>

Gravity is the amount of force that is produced by the earth to attract the object toward the surface and it doubles if the mass is double.

The height of Saturn is the duble of the radius of the given radius of 54,364 km of the planet Saturn which is 108,728 km.

Therefore,  F is 2.980 x 104 N  gravity Gm1 is  2523 kg m₂ is 5.68 x 1026 kg and radius 54,364 km and hight is 108,728 km.

Learn more about gravity, here:

brainly.com/question/4783082

#SPJ1

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Answer:

Ocean waves contain tremendous energy potential. Wave power devices extract energy directly from the surface motion of ocean waves. In many areas of the world, the wind blows with enough consistency and force to provide continuous waves along the shoreline.

6 0
3 years ago
What is the change in density if a sample goes from 3.21 g/L to 5.43 g/mL?
Step2247 [10]

Answer:

\Delta \rho =2.22 g/mL

Explanation:

Hello,

In this case, since a change in science is widely known to be considered as a subtraction between the the final and initial values of two measured variables and is represented via Δ, here the final density is 5.43 g/mL and the initial one was 3.21 g/mL, therefore, the change in density is:

\Delta \rho=\rho _f-\rho _i\\ \\\Delta \rho=5.43g/mL-3.21g/mL\\\\\Delta \rho =2.22 g/mL

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3 0
3 years ago
Which determines the chemical properties of minerals?
azamat
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5 0
3 years ago
How many milliliters of a 1.5 m h2so4 are needed to neutralize 35ml sample of a 1.5 m solution?
DochEvi [55]

Answer:

1) 17.5 mL

Explanation:

Hello,

In this case, the reaction between sulfuric acid and potassium hydroxide is:

H_2SO_4+2KOH\rightarrow K_2SO_4+2H_2O

In such a way, we notice a 1:2 molar ratio between the acid and the base, therefore, at the equivalence point we have:

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And in terms of concentrations and volumes:

2*M_{acid}V_{acid}=M_{base}V_{base}

Thus, we solve for the volume of acid:

V_{acid}=\frac{M_{base}V_{base}}{2*M_{acid}} =\frac{35mL*1.5M}{2*1.5M} \\\\V_{acid}=17.5mL

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5 0
3 years ago
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