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julia-pushkina [17]
1 year ago
11

What species are in the buffer region of a weak acid–strong base titration? How are they different from the species at the equiv

alence point? How are they different from the species in the buffer region of a weak base–strong acid titration?
Chemistry
1 answer:
Misha Larkins [42]1 year ago
3 0

The pH will start high and decrease, as opposed to starting low in increasing, but the buffer region is still at the beginning and the equivalence point is still in the middle.

<h3>What is weak acid?</h3>

Corrosive strength is the propensity of a corrosive, represented by the synthetic recipe HA, to separate into a proton, H+, and an anion. Powerless acids don't totally separate into their particles in water. For instance, HF separates into the H + and F - particles in water, yet some HF stays in arrangement, so it's anything but a solid corrosive. There are a lot more powerless acids than solid acids. Most natural acids are feeble acids. A feeble corrosive isn't totally ionized in arrangement. For instance, hydrofluoric corrosive, HF, is a feeble corrosive. At the point when broken up in water, HF particle exist in balance with H +, which responds with water to shape hydronium, and F - particles. Since the corrosive doesn't totally separate into its ionic parts, it is a frail corrosive.

Learn more about weak acid, visit

brainly.com/question/9091286

#SPJ4

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Answer:

The correct answer is option D.

Explanation:

Rate of the reaction is a change in the concentration of any one of the reactant or product per unit time.

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Rate of the reaction:

R=-\frac{1}{1}\times \frac{d[NO_2]}{dt}=-\frac{1}{1}\times \frac{d[CO]}{dt}

Rate of decrease in nitrogen dioxide concentration is equal to the rate of decrease in carbon monoxide.

Given rate expression of the reaction:

R = k[NO2]^2[CO]

Rate of the reaction on doubling concentration of nitrogen dioxide and carbon monoxide : R'

R'=k(2\times [NO_2])^2(2\times [CO])=8\times k[NO2]^2[CO]=8R

Doubling the concentrations of nitrogen dioxide and carbon monoxide simultaneously will increase the rate of the reaction by a factor of eight.

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Alla [95]

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2 years ago
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svlad2 [7]

Answer:  131 g of bromine is required.

Explanation:

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To calculate the moles, we use the equation:

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Mass of Br_2=moles\times {\text {Molar mass}}=0.816moles\times 160g/mol=131g

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