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3 years ago

how does the increased salinity of the dead sea due to fertiliser industry impact the microscopic organisms that live there

1 answer:

5 0

The sea is called "dead" because its high salinity prevents macroscopic aquatic organisms, such as fish and aquatic plants, from living in it, though minuscule quantities of bacteria and microbial fungi are present. In times of flood, the salt content of the Dead Sea can drop from its usual 35% to 30% or lower.

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stich3 [128]

Answer : The products of the acid-base reaction between $HClO_3$ and LiOH are, $LiClO_3$ and $H_2O$

Explanation :

Neutralization reaction : It is a type of chemical reaction in which an acid react with a base to give salt and water as a product that means it reacts to give a neutral solution. It is also known as acid-base reaction.

The acid-base reaction will be:

$HClO_3+LiOH\rightarrow LiClO_3+H_2O$

Therefore, the products of the acid-base reaction between $HClO_3$ and LiOH are, $LiClO_3$ and $H_2O$

6 0

3 years ago

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A student dissolves 6.2g of aniline c6h5nh2 in 350.ml of a solvent with a density of 1.04/gml . the student notices that the vol

Troyanec [42]

Answer : The correct answer for molarity = 0.19 $\frac{mol}{L}$ and Molality = 0.18 $\frac{mol}{Kg}$ .

Given : Mass of aniline = 6.2 g

Volume of solvent = 350 mL Density of solvent = 1.04 g/mL

1) Molarity : It is defined as number of moles of solute present in Litre of solution . It is expressed as :

$Molarity(M) = \frac{moles of solute(mole)}{volume of solution (L)}$ \

Molairty can be found in following steps :

Step 1 : To calculate mole :

Mole of solute can be calculate using mole formula :

$Mole of solute = \frac{given mass of solute (g)}{molar mass of solute\frac{g}{1 mol}}$

Molar mass of aniline (C₆H₅NH₂) = 93.13 $\frac{g}{1 mol}$

Mass of aniline = 6.2 g

Plugging values in mole formula :

$Mole = \frac{6.2 g}{93.13 \frac{g}{1 mol}}$

Mole = 0.0665 mol

Step 2 : To find volume of solution

Volume of solution = volume of solute + volume of solution

Since addition of aniline does not change final volume , so volume of solvent = volume of solution. Since volume is given in mL , so it need to be converted to L .

1 L = 1000mL

$Volume of solution = \frac{350 mL}{1000mL} * 1 L$

Volume of solution = 0.350 L

Step 3: Plug value of mole and volume in molarity formula :

$Molarity = \frac{0.0665 mol}{0.350 L }$

Molarity = 0.19 M or 0.19 $\frac{mol}{L}$

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2) Molality : It is defined as mole of solute present in Kilogram of solvent . It can be expressed as :

$Molality (m) = \frac{mole of solute (mol)}{Kilogram of solvent (Kg)}$

Following are the steps to calculate molality :

Step 1: To find mole of Solute :

Mole of solute can be found out using mole formula . It is same as done for molarity .

Mole = 0.0665 mol

Step 2 : To find kilogram of solvent :

Mass of solvent can be calculated using density formula as :

$Density \frac{g}{mL} = \frac{mass (g) }{volume (mL)}$

Plugging value in density formula :

$1.04 \frac{g}{mL} = \frac{ mass }{350 mL}$

Multiplying both side by 350 mL

$1.04 \frac{g}{mL} * 350 mL = \frac{x}{350 mL } * 350 mL$

Mass of solvent = 364 g

Since mass is in g, it need to be converted to Kg . ( 1 Kg = 1000 g )

$Mass of solvent = \frac{364 g}{1000g} * 1 Kg$

Mass of solvent = 0.364 Kg

Step 3: Plug values of mole and Kg in molality formula :

$Molality = \frac{0.0665 mol}{0.364 Kg}$

Molality = 0.18 m or 0.18 $\frac{mol}{Kg}$

3 0

3 years ago

Clathrate hydrate research is done by Professor Kend Janda at UC Irvine. Look up clathrate hydrate with a general internet searc

lidiya [134]

Answer:

water, host

Explanation:

Clathrate hydrates are the crystalline water-based solids which physically resembles with the ice, in which the small non-polar molecules or smaller polar molecules with the large hydrophobic moieties are usually trapped inside the "cages" of the hydrogen bonded as well as frozen water molecules.

<u>Clathrate hydrates are the clathrate compounds in which water creates the cage and the water behaves as a host molecule and guest molecule is typically a gas or liquid.</u>

3 0

3 years ago

gamma rays have an approximate wavelength of 1.0x10^-13 meters. what is the approximate energy of a gamma-ray?

Bogdan [553]

Answer:

E = 19.89 × 10⁻¹³ J

Explanation:

Given data:

Wavelength of gamma ray= 1.0× 10⁻¹³ m

Energy of gamma ray = ?

Solution:

Formula:

E = h c/λ

h = plancks constant = 6.63× 10⁻³⁴ js

c = speed of light = 3 ×10⁸ m/s

by putting values,

E = 6.63× 10⁻³⁴ js × 3 ×10⁸ m/s /1.0× 10⁻¹³ m

E = 19.89 × 10⁻²⁶ J.m/ 1.0× 10⁻¹³ m

E = 19.89 × 10⁻¹³ J

8 0

3 years ago

Which changes occur in the composition of the earths layers from the surface to the core

cestrela7 [59]

The mantle is the least hottest

8 0

3 years ago

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how does the increased salinity of the dead sea due to fertiliser industry impact the microscopic organisms that live there​

how does the increased salinity of the dead sea due to fertiliser industry impact the microscopic organisms that live there