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3 years ago

how does the increased salinity of the dead sea due to fertiliser industry impact the microscopic organisms that live there

1 answer:

5 0

The sea is called "dead" because its high salinity prevents macroscopic aquatic organisms, such as fish and aquatic plants, from living in it, though minuscule quantities of bacteria and microbial fungi are present. In times of flood, the salt content of the Dead Sea can drop from its usual 35% to 30% or lower.

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Solution (A) contains 0.01 M of NH4Cl; solution

ArbitrLikvidat [17]

Answer:

NH4Cl, NaCl, Ba(OH)2, NaOH

Explanation:

NH4Cl is an acidic salt formed by the neutralization of a strong acid (HCl) with a weak base (NH3). Hence, it will habe a PH<7 (the lowest PH).

NaCl is a neutral salt,formed by neutralization of a strong acid (HCl) with a strong base (NaOH). Hence, it will have a PH of 7.

Ba(OH)2 is a weak base. Therefore, it will have a PH between 8 and 10.

NaOh meanwhile, is a strong base. Therefore, it will have a PH between 10 to 13.

Hence, we have

NH4Cl < NaCl < Ba(OH)2 < NaOH

5 0

3 years ago

Which indicator would show a pH change from 6 to 7?

tatyana61 [14]

Answer:

Explanation:

1. litmus paper is used when showing a change between a greater range in ph levels - so A and D are automatically a no.

2. methyl red is used to show a range in ph levels between 4.8-6

3. Option C is the only one left so im going to assume its C because its definitely not A, B, or D

7 0

3 years ago

A doctor is testing a new medication and he doesn’t tell the people in the study about the possible side effects of the medicine

Anika [276]

Answer is non compliant

8 0

3 years ago

Read 2 more answers

Lead can be prepared from galena [lead(II) sulfide] by first roasting the galena in oxygen gas to form lead(II) oxide and sulfur

Vesna [10]

Answer:

a) Step 1:

$2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)$

Step 2:

$2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)$

b) The overall balanced reaction for given process is ;

$3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)$

Explanation:

Galena = $PbS$

Lead(II) oxide = $PbO$

Sulfur dioxide = $SO_2$

Step 1:

Roasting the galena in oxygen gas to form lead(II) oxide and sulfur dioxide.

Balanced equation of step 1:

$2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)$ ..[1]

Step 2:

Heating the metal oxide with more galena forms the molten metal and more sulfur dioxide.

Balanced equation of step 2:

$2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)$ ..[2]

For over all reaction add [1] and [2]. The overall balanced reaction for given process is ;

$3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)$

5 0

4 years ago

Read 2 more answers

. Write the following isotope in nuclide notation (e.g., “ ”): copper-70

vekshin1

Answer:

${\boxed{\text{$_{29}^{70}${Cu}}}$

Explanation:

The atomic number (Z) of copper is 29 and this isotope has an atomic mass (A) of 70.

The general symbol for an isotope E is $_{Z}^{A}\text{E}$ .

The atomic number is a left subscript, and the atomic mass is a left superscript.

$\rm {\text{The nuclide notation for copper-70 is }}{\boxed{\textbf{$_{29}^{70}${Cu}}}$

4 0

3 years ago

how does the increased salinity of the dead sea due to fertiliser industry impact the microscopic organisms that live there​

how does the increased salinity of the dead sea due to fertiliser industry impact the microscopic organisms that live there