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Snowcat [4.5K]
2 years ago
14

At the top of a hill, an athlete on a skateboard has X joules of mechanical energy. How much mechanical energy will she have at

the bottom of the hill? Ignore the effects of friction. X joules less than X joules more than X joules There is not enough information to know.
Chemistry
1 answer:
ExtremeBDS [4]2 years ago
5 0

If an athlete has X joules of mechanical energy at the top of the hill, he will have the same X amount of energy at the bottom of the hill.

<h3>What is mechanical energy?</h3>

Mechanical energy is the addition of kinetic and potential energy. It can be either kinetic or potential energy.

It is the energy possessed by the position or the motion of the body.

It is the energy present to perform any work.

So, the athlete will have X joule of energy at the top and bottom of the hill.

Thus, the correct option is a, X joules.

Learn more about mechanical energy

brainly.com/question/20030300

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At its critical point, ammonia has a density of 0.235 g cm23. You have a special thick­walled glass tube that has a 10.0­mm outs
salantis [7]

Answer:

\large \boxed{\text{69.3 mg}}

Explanation:

1. Volume of sealed tube

Assume the sealed tube is a right circular cylinder in which the cap and the base are also 4.20 mm thick.

Its outside dimensions are 155 mm long × 10.0 mm diameter.

Its inside dimensions are

h = 155 mm - 2 × 4.20 mm = 146.6 mm

r = 5.0 mm - 4.20 mm = 0.8 mm

V = πr²h = π(0.8)²× 146.6 mm³ = 294.8 mm³ = 0.2948 cm³

2. Calculate the mass of NH₃

\begin{array}{rcl}\text{Density} & = & \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho & = &\dfrac{m}{V}\\\\0.235 \text{ g$\cdot$ cm}^{-3} & = & \dfrac{m}{\text{0.2948 cm}^{3}}\\\\m & = & \text{0.0693 g}\\& = & \textbf{69.3 mg}\\\end{array}\\\text{You must seal $\large \boxed{\textbf{69.3 mg}}$ of ammonia in the tube.}

4 0
3 years ago
Someone pls help me I will make you brain
Katena32 [7]

Answer:

it is actually b because i did this i picked b and got it right

Explanation:

4 0
3 years ago
Calculate the relative density of carbon monoxide and carbon dioxide with respect to air.
JulsSmile [24]
Density is proportional to molar mass, assuming pressure and temperature remain constant. Therefore, since CO has a molar mass of 28 and CO2 has a molar mass of 44:
The relative density of CO vs air is 28/29 = 0.9655.
The relative density of CO2 vs air is 44/29 = 1.517.

3 0
3 years ago
4) Ethanol has a density of 0.8 g/cm3. <br> What is the mass of 225 cm3 of ethanol
AveGali [126]

Answer:

\huge\boxed{\sf m = 180\  g}

Explanation:

<u>Given:</u>

Density = ρ = 0.8 g/cm³

Volume = V = 225 cm³

<u>Required:</u>

Mass = m = ?

<u>Formula:</u>

m = ρV

<u>Solution:</u>

m = (0.8)(225)

m = 180 g

\rule[225]{225}{2}

Hope this helped!

<h2>~AnonymousHelper1807</h2>
7 0
3 years ago
how much heat is needed to raise the temperature of 75 g of a substance by 15 C when the specific heat is 0.92 J/g-C?
IRINA_888 [86]
Answer is: 1035 joules of heat is needed.<span>
m(substance</span>) = 75 g.<span>
ΔT(substance</span>) = 15°C.<span>
cp(substance</span>) = 0,92 J/g°C.<span>
Q = m</span>(substance) · ΔT(substance) · cp(substance).<span>
Q = 75 g · </span>15°C · 0,92 J/g°C<span>.
Q = 1035 J = 1,035 kJ.</span>
3 0
3 years ago
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