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3 years ago

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Compare and contrast basic research applied research and technological development in chemistry

1 answer:

deff fn [24]3 years ago

5 0

Human beings like to categorize things. We don't like amorphous groupings of ideas floating around. It just makes things difficult to comprehend. I'm not going to shock anyone when I say that one thing that is divided into categories is research<span>. One way to make research topics more manageable is dividing the topics by asking the question, 'What will this be used for?</span>

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The standard free-energy change for this reaction in the direction written is 23.8 kJ/mol. The concentrationsof the three interm

Natali [406]

Answer: The actual free-energy change for the reaction -8.64 kJ/mol.

Explanation:

The given reaction is as follows.

Fructose 1,6-bisphosphate $\rightleftharpoons$ Glyceraldehyde 3-phosphate + DHAP

For the given reaction, $\Delta G^{o}$ is 23.8 kJ/mol.

As we know that,

$\Delta G = \Delta G^{o} + RT ln Q$

Here, R = 8.314 J/mol K, T = $37^{o} C$

= (37 + 273) K

= 310.15 K

Fructose 1,6-bisphosphate = $1.4 \times 10^{-5}$ M

Glyceraldehyde 3-phosphate = $3 \times 10^{-6}$ M

DHAP = $1.6 \times 10^{-5}$ M

Expression for reaction quotient of this reaction is as follows.

Reaction quotient = $\frac{[DHAP][\text{glyceraldehyde 3-phosphate}]}{[/text{Fructose 1,6-bisphosphate}]}$

Q = $\frac{1.6 \times 10^{-5} \times 3 \times 10^{-6}}{1.4 \times 10^{-5}}$

= $3.428 \times 10^{-6}$

Now, we will calculate the value of $\Delta G$ as follows.

$\Delta G = \Delta G^{o} + RT ln Q$

= $23800 + 8.314 \times 310.15 \times ln(3.428 \times 10^{-6})$

= -8647.73 J/mol

= -8.64 kJ/mol

Thus, we can conclude that the actual free-energy change for the reaction -8.64 kJ/mol.

7 0

3 years ago

A round character is one-sided and does not show much of his/her emotions or conflicts.

My name is Ann [436]

Answer:

true

Explanation:

Round characters tend not to show a lot of their emotions or feelings.

7 0

3 years ago

Calculate the number of moles of each compound, given the number of molecules.

anastassius [24]

Answer:

1. $2.46\times 10^{21}$ molecules of CO₂

2. 10⁴ molecules of H₂O

3. 8.75×10³² molecules of C₆H₁₂O₆

Explanation:

1. $2.46\times 10^{21}$ molecules of CO₂

2. 10⁴ molecules of H₂O

3. 8.75×10³² molecules of C₆H₁₂O₆

5 0

3 years ago

Convert 1.3902 hectoliters to centiliters.

hram777 [196]

<span>The answer is 13,902 centiliters.

</span>

8 0

4 years ago

Read 2 more answers

In which of the ions do all x-o bonds (x indicates the central atom) have the same length?

Radda [10]

<span>Answer: All of the ions do all x-o bonds (x indicates the central atom) have the same length.</span>

7 0

4 years ago