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11Alexandr11 [23.1K]
3 years ago
7

Problem Page A table of values of a linear function is shown below. x −1 0 1 2 3 y −6 −8 −10 −12 −14 Find the slope and y -inter

cept of the function's graph, and find the equation for the function.
Mathematics
1 answer:
Ivenika [448]3 years ago
3 0
When x=0, y=-8, so that is the y-intercept.

When x increases by 1, y decreases by 2, so the slope is -2.

The equation of the function is
.. y = -2x -8
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My book is 58 pages. I have already read 13 pages. I plan to read 5 pages each day until I finish the book.
ELEN [110]
C. (58-13)÷5=d

hope this helps, Buddy
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The length of a rectangle is 2 units more than the width. The area of the rectangle is 35 units. What is the width, in units, of
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A music store gives every 20th costumer a 5$ gift card.Every 50th customer gets a 10$ gift card. Which customer will be the firs
prisoha [69]

Answer:

100th customer is the first desired customer who received both the gift cards.

Step-by-step explanation:

$5 gift card is received by every 20th Customer.

⇒ The customers who receive this $5  card are:

20th Customer, 40th Customer , 60th Customer , 80th Customer, <u>100th</u><u> Customer</u>, 120th Customer .... and so on

Also, $10 gift card is received by every 50th Customer.

⇒ The customers who receive this $10  gift are:

50th Customer, <u>100th</u><u> Customer</u> , 150th Customer , 200th Customer ......

Among all the customers the 100th customer is the first customer who receives $5 gift card as well as the $10 gift card.

Hence, 100th customer is the first desired customer who received both the gift cards.

6 0
3 years ago
There were 700 people in the auditorium. 60% of them were adults and the rest were children. how many adults were in the auditor
ollegr [7]

.60 \times 700 = 420 \\ 700 - 420 = 280
First I found the number of adults by multiplying .60 by 700. It was 420. From there all I had to do was subtract it from 700. Revealing the number of children to be 280.
5 0
3 years ago
A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on
SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

Z_{1-\alpha /2}= Z_{0.95}= 1.645

[10.41±1.645*(\frac{3.71}{\sqrt{28} } )]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0
4 years ago
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