Answer:
7/√2 cm
Step-by-step explanation:
Area of circle = 77 cm^2
=> π(r)^2 = 77
=> (22/7) x (r)^2 = 77
=> (r)^2 = (77 x 7) / 22
=> (r)^2 = 49/2
=> (r) = 7/√2 cm
Answer:
label a graph doing -5,-8, and 4,4 use the formula which is
d = ( x 2 − x 1 )^2 + ( y 2 − y 1 )^2
x2-x1 = 4–2= 2 Y2–Y1 = 1–3 = -2 d=√(2)^2+(-2)^2 =√4+4 = √8 d= 2√2
so this is the same thing the person above me did but I've been typing this out so long I want to go ahead and submit anyway
Answer:
A (2, -8/5)
Step-by-step explanation:
The answer would be A I believe. This is because to get from C to D, it would be going down 6 and to the right by 10.
To make CP = 3/5CD. We multiply how much we move by 3/5:
-6 * 3/5 = -18/5 (note that the 6 would be negative because its going down)
and 10 * 3/5 = 6
Then we add these values to the coordinates of C:
(-4 + 6, 2 - 18/5) =
(2, -8/5). So A would be the answer.
Answer:
The approximate percentage of SAT scores that are less than 865 is 16%.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean of 1060, standard deviation of 195.
Empirical Rule to estimate the approximate percentage of SAT scores that are less than 865.
865 = 1060 - 195
So 865 is one standard deviation below the mean.
Approximately 68% of the measures are within 1 standard deviation of the mean, so approximately 100 - 68 = 32% are more than 1 standard deviation from the mean. The normal distribution is symmetric, which means that approximately 32/2 = 16% are more than 1 standard deviation below the mean and approximately 16% are more than 1 standard deviation above the mean. So
The approximate percentage of SAT scores that are less than 865 is 16%.
