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Svetach [21]
3 years ago
15

Does the mixed number 4 3/4 make each equation true? Choose Yes or No for each equation.

Mathematics
2 answers:
IRISSAK [1]3 years ago
7 0
1 yes 2 no 3 no 4 no
Mila [183]3 years ago
6 0

Answer:

1 is Yes, 2 is No, 3 is No, 4 is No

Step-by-step explanation:

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Use the drawing tool(s) to form the correct answers on the provided graph.
NISA [10]

Answer:

2x– 3y = –18

3x + y = -5

Converting the equation in slope-intercept form

2x-3y= -18

-3y= -2x-18

-3y= -(2x+18)

3y=2x+18

y=(2x+18)/3

And for equation 2

y= -5-3x

For plotting the graph, the online graphing calculator desmos.com can be used.

The points can be calculated by putting negative and positive values of x in both equations.

The graph is attached as a picture.

As we can see from the graph that two lines intersect at (-3,4) so it is the solution of the given system of linear equations.

3 0
3 years ago
Read 2 more answers
Naoko found a deck of playing cards that had been dropped onto the floor. she picked up at least one card. she may have picked u
quester [9]
The answer to this question would be: 2*52! -1

In this case, the card is either picked up by Naoko or they are not picked up. That means there are two possible outcomes for each card. For 52 card, the possibility should be:
2*52!

If Naoko needs to pick at least one, the possibilities become one less because "no card picked" possibility is ruled out
8 0
4 years ago
You need 3 sticks of butter for every 24 cookies you bake. How many cookies can you make with 7 sticks of butter?
neonofarm [45]
Just times 24 times 7 there it’s simple
5 0
3 years ago
Read 2 more answers
Let X = the time between two successive arrivals at the drive-up window of a local bank. If X has an exponential distribution wi
Illusion [34]

Answer:

(a) E(X) = 1

(b) \sigma_X =1

(c)  P(X ≤ 1) = 0.6321

(d) P(2 ≤ X ≤ 5) = 0.1286

Step-by-step explanation:

From the given information; Let consider X to be the time between two successive arrivals at the drive-up window of a local bank.

However; If X is regarded as the exponential distribution with λ = 1 which is identical to a standard gamma distribution with ∝ = 1

The objective is to compute the following :

(a) The expected time between two successive arrivals is;

E(X) = \dfrac{1}{\lambda}

E(X) = \dfrac{1}{1}

E(X) = 1

(b)  The standard deviation of the time between successive arrivals is;

\sigma_X = \sqrt{\dfrac{1}{\lambda^2}}

\sigma_X ={\dfrac{1}{\lambda}}

\sigma_X ={\dfrac{1}{1}}

\sigma_X =1

(c)  P(X ≤ 1)

P(X ≤ 1) = 1 - e⁻¹

P(X ≤ 1) = 0.6321

(d) P(2 ≤ X ≤ 5)

P(2 ≤ X ≤ 5) = [1 -  e⁻⁵] - [1 - e⁻²]

P(2 ≤ X ≤ 5) = 0.9933 - 0.8647

P(2 ≤ X ≤ 5) = 0.1286

7 0
3 years ago
This is overdue and I can’t figure it out. Plz help
Svetach [21]

Answer:

One soultion

Step-by-step explanation:

5 0
3 years ago
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