1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mrac [35]
2 years ago
11

Stu's teacher wrote his test score as a fraction. He wrote 7/10. What is his score as a percent

Mathematics
2 answers:
zheka24 [161]2 years ago
7 0

Answer:

that would be a seventy (70)

VladimirAG [237]2 years ago
7 0

Answer:

70%

Step-by-step explanation:

You might be interested in
Really need help on #15 please.
ollegr [7]

Step-by-step explanation:

Let's call L the length and W the width.  The length is 10 feet longer than the width, so:

L = W + 10

The area is the length times width, so:

119 = LW

Substituting:

119 = (W + 10) W

119 = W² + 10W

0 = W² + 10W − 119

0 = (W + 17) (W − 7)

W = -17 or 7

Since W must be positive, W = 7.

L = W + 10

L = 17

The length and width are 17 feet and 7 feet, respectively.

5 0
3 years ago
Please help me with Part C of this question!!!
anzhelika [568]

Answer:

  a. 3/4 inches per minute

  b. -1 1/8 inches per minute

  c. B is fastest; 1 1/8 is more than 3/4

Step-by-step explanation:

A <em>change</em> is a <em>difference</em>. A <em>rate of change</em> is <em>one difference divided by another</em>, usually the change in y-value divided by the change in x-value.

__

<h3>a.</h3>

The change in elevation is the difference between the elevation at the end of the period (6 inches) and the elevation at the beginning of the period (3 inches). The change in time period is the difference between the end time (8 min) and the beginning time (4 min).

  change in elevation per minute = (6 -3 inches)/(8 -4 min)

  = (3 inches)/(4 min) = 3/4 inches/minute

__

<h3>b.</h3>

Similarly, ...

  change in elevation per minute = (3 -7 1/2 inches)/(18 -14 min)

  = (-4 1/2 inches)/(4 min) = -1 1/8 inches/minute

__

<h3>c.</h3>

We know that 3/4 is more than -1 1/8, but when we talk about the "fastest rate of change", we're generally interested in the magnitude--the value without the sign. That means we understand a rate of change of -1 1/8 inches per minute to be "faster" than a rate of change of 3/4 inches per minute.

The rate of change from Part B is fastest. 1 1/8 inches per minute is more than 3/4 inches per minute.

6 0
2 years ago
Calculus Problem
Roman55 [17]

The two parabolas intersect for

8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2

and so the base of each solid is the set

B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, |x^2-(8-x^2)| = 2|x^2-4|. But since -2 ≤ x ≤ 2, this reduces to 2(x^2-4).

a. Square cross sections will contribute a volume of

\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x

where ∆x is the thickness of the section. Then the volume would be

\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x

We end up with the same integral as before except for the leading constant:

\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx

Using the result of part (a), the volume is

\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x

and using the result of part (a) again, the volume is

\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}

7 0
2 years ago
Hi guys<br>I need 3 minus and plus operations with answer thx!​
nata0808 [166]

1999+1001=3000 1091+1009=3000 2000+1000=3000

3000-1001=1999 3000-1009=1091 3000-2000=1000

8 0
2 years ago
37.06 - (-26) +34.67
maxonik [38]

Answer:

97.73

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Other questions:
  • Help plz I will giv brainliest if it's right
    11·1 answer
  • How do I get the numbers for the x and y Table ?
    15·1 answer
  • the amount of money rqised at a charity fundraiser varies directly with the number of attendees. the amount of money raised by 1
    15·1 answer
  • At an airport, it cost 7 to park for one hour and 5 per hour for each additional hour.Let x represent the number hours parked.wr
    13·1 answer
  • The direct distance from a starting point to a finish line is 20 miles. Unfortunately, you can't take the direct route. If you t
    11·1 answer
  • Latih Diri 2.1b
    11·1 answer
  • zoey invested $230 in a account interest rate was 6.3% daily to the nearest hundred dollars, would be after 12 years
    6·1 answer
  • Right triangle hypotenuse is 16 angle is 22° and adjacent angle is x
    13·1 answer
  • What is the nth term rule of the quadratic sequence below?
    12·1 answer
  • Classify each number below as an integer or not.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!