Answer:
The answer to your question is 21 g of CO₂
Explanation:
Balanced Reaction
C₃H₈ + 6O₂ ⇒ 3CO₂ + 4H₂O
Data
mass of C₃H₈ = 7 g
mass of O₂ = 98 g
Determine the limiting reactant
Molecular mass of C₃H₈ = (12 x3) + (1 x 8) = 36 + 8 = 44 g
Molecular mass of Oxygen = 16 x 12 = 192 g
Theoretical proportion C₃H₈ / O₂ = 44 / 192 = 0.23
Experimental proportion C₃H₈ / O₂ = 7 / 98 = 0.07
As the proportion diminishes in the experiment, the excess reagent is the oxygen and the limiting reactant is propane.
- Calculate the mass of CO₂
44 g of C₃H₈ ---------------- 3(44) of CO₂
7 g of C₃H₈ --------------- x
x = (7 x 3(44)) / 44
x = 924 / 44
x = 21 g of CO₂
