When battery discharge / delivering current the lead at the anode is oxidized
that is ;
pb---->pb+ 2e-
since the lead ions are in presence of aquous sulfate in insoluble lead sulfate precipitate onto the electrode
the overall reaction at the anode is therefore
Pb + SO4^2- ---> PbSO4 + 2e-
40°F or less for deli to still be good
Answer:
6.4
Explanation: pH
+
pOH
=
14
So if
pH
=
7.6
then
pOH
=
14
−
pH
=
6.4
Explanation:
Wrote this out spaced so it's more clear.
Dissociation of NaCl in water is given as below,
NaCl ₍s₎ → Na⁺ ₍aq₎ + Cl⁻ ₍aq₎
According to this balanced equation the moles on RHS and LHS are as,
Moles on LHS,
NaCl ₍s₎ = 1 Mole
Moles on RHS,
Na⁺ ₍aq₎ = 1 Mole
Cl⁻ ₍aq₎ = 1 Mole
Result:
<span>When one mole of sodium chloride dissociates in water, it produces 2 Moles of Ions.</span>
