Ask question

Ask question

All categories

3 years ago

11

Sulfuric acid reacts with aluminum hydroxide by double replacement. if 34 g of sulfuric acid react with 33 g of aluminum hydroxi

de, identify the limiting reactant.

1 answer:

Lina20 [59]3 years ago

4 0

Answer is: sulfuric acid is the limiting reactant.
Chemical reaction: 3H₂SO₄ + 2Al(OH)₃ → Al₂(SO₄)₃ + 6H₂O.
m(H₂SO₄) = 34 g.
n(H₂SO₄) = m(H₂SO₄) ÷ M(H₂SO₄).
n(H₂SO₄) = 34 g ÷ 98 g/mol.
n(H₂SO₄) = 0,346 mol.
m(Al(OH)₃) = 33 g.
n(Al(OH)₃) = 33 g ÷ 78 g/mol.
n(Al(OH)₃) = 0,423 mol.
From chemical reaction: n(H₂SO₄) : n(Al(OH)₃) = 3 : 2.

You might be interested in

How many grams of phosphorus are in 500.0 grams of calcium phosphide? (i need the work also)

kvv77 [185]

Answer:

$\boxed{\text{170.0 g P}}$

Explanation:

The formula of calcium nitride is Ca₃P₂.

The masses of each element are:

$\begin{array}{lrcr}\text{3Ca:} & 3 \times 40.08&=& \text{120.24 u}\\\text{2P:} & 2\times 30.97&=& \text{61.94 u}\\& \text{TOTAL} & = & \text{182.18 u}\\\end{array}$

So, there are 61.94 g of P in 182.18 g of Ca₃P₂.

In 500 g of Ca₃P₂:

$\text{Mass of P} = \text{500.0 g Ca$_{3}$P$_{2}$} \times \dfrac{\text{61.94 g P}}{\text{182.18 g Ca$_{3}$P$_{2}$}} = \text{170.0 g P}$

There are $\boxed{\textbf{170.0 g P}}$ in 500.0 g of Ca₃P₂.

3 0

2 years ago

Use the data given below to construct a Born-Haber cycle to determine the heat of formation of KCl. Δ H°(kJ) K(s) → K(g) 89 K(g)

AURORKA [14]

Explanation:

The net equation will be as follows.

$K(s) + Cl_{2}(g) \rightarrow KCl(s)$

So, we are required to find $\Delta H_{formation}$ for this reaction.

Therefore, steps involved for the above process are as follows.

Step 1: Convert K from solid state to gaseous state

$K(s) \rightarrow K(g)$ , $\Delta H_{1}$ = 89 kJ

Step 2: Ionization of gaseous K

$K(g) \rightarrow K^{+}(g) + e^{-}$ , $H_{2}$ = 418 KJ

Step 3: Dissociation of $Cl_{2}$ gas into chlorine atom .

$\frac{1}{2} Cl_{2}(g) \rightarrow Cl(g)$ , $\Delta H_{3} = \frac{244}{2}$ = 122 KJ

Step 4: Iozination of chlorine atom.

$Cl(g) + e^{-} \rightarro Cl^{-}(g)$ , $H_{4}$ = -349 KJ

Step 5: Add $K^{+}$ ion and $Cl^{-}$ ion formed above to get KCl .

$K^{+}(g) + Cl^{-}(g) \rightarrow KCl(s)$ , $H_{5}$ = -717 KJ

Now, using Born-Haber cycle, value of enthalpy of the formation is calculated as follows.

$\Delta H_{f} = \DeltaH_{1} + \Delta H_{2} + \Delta H_{3} + \Delta H_{4} + \Delta H_{5}$

= 89 + 418 + 122 - 349 - 717

= - 437 KJ/mol

Thus, we can conclude that the heat of formation of KCl is - 437 KJ/mol.

5 0

3 years ago

Which of the following is not an effect of climate change?

user100 [1]

Answer:

coastal flooding

Explanation:

8 0

3 years ago

Read 2 more answers

How do the transition metals in Period 4 affect the pattern of ionization energies in Group 3A(13)? How does this pattern compar

serious [3.7K]

The transition metals is Group 3B(13), there is a smoother decrease in ionization energy because these group contains only the transition metals.

The quantity of strength needed to remove an electron from a selected gaseous atom or ion is called the ionisation electricity Group 3B(13) . not just the atoms that are gases at ambient temperature are protected via it; all the elements at the periodic desk are included.

Ionization energy:

the desired energy to put off an outermost electron from a neutral atom is known as ionization electricity.

In typically, up to down inside the periodic table ionization power is decreases but in group 3A and Group 3B(13) (thirteen) it's miles irregular because the arrival of the transition metals in four length due to this Ga, In and Tl elements indicates better the ionization energies so there's no pattern on this organization.

To learn more about Group 3B(13) refer the link:

brainly.com/question/5489194

#SPJ4

6 0

1 year ago

flammability is a material's ability to burn in the presence of a. hydrogen b. nitrogen c. oxygen d. carbon dioxide

Olegator [25]

Oxygen.

<h3>Further explanation</h3>

Chemical properties can be observed only when the substance changes into one or more different substances through chemical reactions or transformations. One of the chemical properties is flammability.

Flammability is a material's ability to burn in the presence of oxygen.

Remember, oxygen doesn't burn. Precisely flammable substances obtain substances that burn. Oxygen remains an oxidizing agent, which means it supports the combustion process. Oxygen causes other objects to catch fire at low temperatures and burns hotter and faster. But oxygen itself does not burn. Consequently, if you at present deliver fuel and fire, adding oxygen will provide the fire.

Carbon dioxide is the result of combustion. An example can be seen in firewood in a fireplace. One of the chemical properties of carbon-based wood is having the ability to burn. Chemically the wood turns into carbon dioxide when it burns and leaves a residue of ash. Furthermore, this ash residue cannot be turned back into the wood. Chemical changes result in new substances.

Consider an example of a combustion reaction to methane gas:

$\boxed{ \ CH_4_{(g)} + 2O_2_{(g)} \rightarrow CO_2_{(g)} + 2H_2O_{(g)} \ }$

Our balanced equation for methane combustion implies that every one CH₄ molecule reacts with two O₂ molecules. The product of combustion is one carbon dioxide molecule and two steam or water vapor molecules.

<h3>Learn more</h3>

Calculating the pH value of weak base brainly.com/question/9040743
About the solution as a homogeneous mixture brainly.com/question/637791
The chemical formula of nitrobenzene brainly.com/question/2861241

Keywords: flammability, a material's ability to burn in the presence of oxygen, hydrogen, nitrogen, carbon dioxide, chemical properties, reactions, the combustion process, oxidizing agent, the result

4 0

3 years ago

Read 2 more answers