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Hunter-Best [27]
2 years ago
4

a person is hearing two sound waves simultaneously. one has a period of 1.50 ms and the other one a period of 1.54 ms. what is t

he period of the beat due to these two waves?
Physics
1 answer:
sammy [17]2 years ago
7 0

The period of the beat due to these two waves is 0.058 s.

<h3>What is frequency?</h3>

Frequency describes the number of waves that pass a fixed place in a given amount of time.

Frequency is also the inverse of period of a wave.

f = 1/T

<h3>Frequency of first wave</h3>

f₁ = 1/T1 = 1/(1.5 x 10⁻³)

f₁ = 666.67 Hz

<h3>Frequency of second wave</h3>

f₂ = 1/T₂

f₂ = 1/(1.54 x 10⁻³)

f₂ = 649.35 Hz

<h3>Beat due to these two waves</h3>

Fb = f₁ - f₂

Fb = 666.67 Hz - 649.35 Hz

Fb = 17.32 Hz

<h3>Period of the beat due to the two waves</h3>

T = 1/fb

T = 1/17.32

T = 0.058 s

Thus, the period of the beat due to these two waves is 0.058 s.

Learn more about beat frequency here: brainly.com/question/3086912

#SPJ1

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