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Temka [501]
4 years ago
5

13. A nuclear decay chain represents

Physics
1 answer:
murzikaleks [220]4 years ago
5 0

Answer:

a series of  decays producing sequentially more stable nuclei

Explanation:

A nuclear decay chain represents a series of decays producing sequentially more stable nuclei.

  • For every atomic nucleus, there is a specific neutron/proton ratio which ensures the stability of the nucleus.
  • Any nucleus with a neutron/proton combination different from its stability ratio (i.e either too many neutrons or too many protons) will be unstable and split into one or more other nuclei with the attendant emission of small particles of matter.
  • The decay process is a continuous chain reaction steps.
  • Until stability of the nucleus is attain, it continues.
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What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates
34kurt

The given question is incomplete. The complete question is as follows.

A parallel-plate capacitor has capacitance C_{0} = 8.50 pF when there is air between the plates. The separation between the plates is 1.00 mm.

What is the maximum magnitude of charge that can be placed on each plate if the electric field in the region between the plates is not to exceed 3.00 \times 10^{4} V/m?

Explanation:

It is known that relation between electric field and the voltage is as follows.

             V = Ed

Now,  

              Q = CV

or,           Q = C \times Ed

Therefore, substitute the values into the above formula as follows.

              Q = C \times Ed

                  = 8.50 pF \times (\frac{10^{-12} F}{1 pF})(3 \times 10^{4} m/s)(1 mm)(\frac{10^{-3} m}{1 mm})

                  = 2.55 \times 10^{-10} C

Hence, we can conclude that the maximum magnitude of charge that can be placed on each given plate is 2.55 \times 10^{-10} C.

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