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Dima020 [189]
3 years ago
8

A sprinter completes a 400m race (one lap around the track). Mr Borst thinks the magnitudes of her distance and displacement are

equalIs he correct?
Physics
1 answer:
GalinKa [24]3 years ago
7 0

Answer:

No

Explanation:

Displacement is how far between your initial and finishing position.

If one lap around the track is 400 m and the sprinter ran 1 lap around the track. Then the sprinter's distance is 400 m and their displacement is 0 m

If the sprinter ran 400 m in a straight line however, then it would be equal.

But since the sprinter ran 1 lap around there is no displacement.

I hope this helped you...  

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A student weighing 700 N climbs at constant speed to the top of an 8 m vertical rope in 10 s. The average power expended by the
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Answer:

The average power the student expended to overcome gravity is 560W, Watts is a units of work it is Joules /time or kg*m^{2}/ s^{3}

Explanation:

Weight = 700N

F= m*g*h \\m*g= 700N\\F= 700N*h\\F=700N*8m\\F= 5600 N*m \\F=5600 J

The power is the work in (Joules) or (N*m) in a determinate time (s) to get Watts (W) units for work

Work= \frac{5600 J}{10s} = \frac{5600 \frac{kg*m^{2} }{s^{2} } }{10 s}  \\Work= 560\frac{kg*m^{2} }{s^{3} } \\Work =560 W

3 0
2 years ago
The weakest type of friction that occurs between solid surfaces is _____ friction
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Answer:

Static, sliding, and rolling friction occur between solid surfaces. Static friction is strongest, followed by sliding friction, and then rolling friction, which is weakest. Fluid friction occurs in fluids, which are liquids or gases.

Explanation:

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Where does cosmic microwave background radiation come from? A. It is radiation produced by pulsars and black holes that warps ou
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C. It is radiation leftover from the Big Bang

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2 years ago
Calculate the potentia energy of a car with a mass of 3800kg that is on a hill 110 meters above sea level? USE 10 instead of 9.8
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Potential energy (PE ) = m g h

Where:

m = mass = 3800 kg

g = acceleration due gravity = 10 m/s^2

h = heigth = 110 meters

Replacing:

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7 0
11 months ago
A crate is placed on an adjustable, incline board. the coefficient of static friction between the crate and the board is 0.29.
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Let the angle be Θ (theta)

Let the mass of the crate be m.

a) When the crate just begins to slip. At that moment the net force will be equal to zero and the static friction will be at the maximum vale.

Normal force (N) = mg CosΘ

μ (coefficient of static friction) = 0.29

Static friction = μN = μmg CosΘ

Now, along the ramp, the equation of net force will be:

mg SinΘ - μmg CosΘ = 0

mg SinΘ = μmg CosΘ

tan Θ = μ

tan Θ = 0.29

Θ = 16.17°

b) Let the acceleration be a.

Coefficient of kinetic friction = μ = 0.26

Now, the equation of net force will be:

mg sinΘ - μ mg CosΘ = ma

a = g SinΘ - μg CosΘ

Plugging the values

a = 9.8 × 0.278 - 0.26 × 9.8 × 0.96

a = 2.7244 - 2.44608

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Hence, the acceleration is 0.278 m/s^2

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2 years ago
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