(x+4)^2 / 9 - (y+3)^2 / 16 = 1
a^2 = 16 and b^2 = 9
a = +4 and -4
b = +3 and -3
Center is (-4, -3)
Vertices is (-4 + a, -3) and (-4 - a, -3)
Vertices is (-1, -3) and (-7, -3)
Answer:
Givens:
Using this information we could recur to SAS postulate to demonstrate the congruence of this pair of triangles. We already have one side and one angle congruent, we just need to demonstrate that
, that will prove the complete congruence.
So, based on the given coordinates, we're able to calculate the length of each side and find if they are the same. We use this formula:

Therefore,
, because they have the same length.
Now, based on these congruences:
We demonstrate by the Side-Angle-Side (SAS) postulate that ΔABC ≅ ΔDEF.
then the inequality would be x<70
Answer:
Step-by-step explanation:
3,9,12,(15),16,18,21
mean (middle number) = 15
Q1 = 9.....the middle number of the numbers before the mean
Q3 = 18...the middle number of the numbers after the mean
interquartile range (IQR) = Q3 - Q1 = 18 - 9 = 9 <==
.5 times four is 3 plus one quarter is 2.33 times 4 is 9.32 plus 75 is 10.07plus 24 is 24.07 then 32 and answer is 56.07