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11 months ago

Is the H¬O bond in water nonpolar covalent, polar covalent, or ionic? Define each term, and explain your choice.

Chemistry

1 answer:

nydimaria [60]11 months ago

5 0

Like hydrogen fluoride (HF), water (H2O) is a polar covalent molecule.

The electron pair in a non-polar covalent bond is shared equally by the two bonded atoms, but in a polar covalent bond, the electron pair is shared unequally by the two bonded atoms. Differences in electronegativity are what lead to polar bonding.

The entire transfer of valence electron(s) between atoms is referred to as an ionic bond. It is a kind of chemical connection that produces two ions with opposing charges. In ionic bonding, the nonmetal takes the lost electrons to form a negatively charged anion while the metal loses them to become a positively charged cation.

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You might be interested in

Convert 6.71 moles NH3 to number of molecules.

svetlana [45]

Answer: There are $40.41 \times 10^{23}$ molecules present in 6.71 moles of $NH_{3}$ .

Explanation:

Given: Moles of $NH_{3}$ = 6.71 mol

According to the mole concept, 1 mole of every substance contains $6.022 \times 10^{22}$ molecules.

Therefore, molecules present in 6.71 moles are calculated as follows.

$Molecules = moles \times 6.022 \times 10^{23}\\= 6.71 \times 6.022 \times 10^{23}\\= 40.41 \times 10^{23}$

Thus, we can conclude that there are $40.41 \times 10^{23}$ molecules present in 6.71 moles of $NH_{3}$ .

6 0

2 years ago

What type of intermolecular forces are expected between 4-methylcyclohexanone molecules?

Keith_Richards [23]

The answer is dipole-dipole and dipole-induced dipole forces.

The dipole-induced dipole is a kind of interaction induced by a polar molecule by disturbing the arrangement of electrons.

In methyl cyclohexanone molecules, there is a permanent dipole moment due to dipole moment vectors not canceling.
There is induction of dipole by disturbing the electronic arrangement.
A permanent dipole moment is created in this interaction.
Dipole-dipole interactions are defined as the forces that is formed from the close linkage of permanent or induced dipoles.
These forces are called Van der Waal forces.
Proteins contain a large number of these interactions, which vary considerably in strength.

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7 0

1 year ago

If the outside of your flask is not dry when the first mass determination is made and it is dried for the second mass determinat

svlad2 [7]

Answer:

You'll experience a grater deviation

Explanation:

You'll experience a greater deviation in your measurements, meaning your measures will have a bigger difference between them, and the greater these deviations the less accurate will be the measuring. This happens mainly because you're not replicating the measurement with the exact same conditions, in one of them you'll have an extra mass from the water.

I hope you find this information useful and interesting! Good luck!

8 0

2 years ago

Making solutions is an extremely important component to real-life chemistry. If you make 3.00 L of a solution using 90.0 g of so

kumpel [21]

Answer:

Final concentration of NaOH = 0.75 M

Explanation:

For $NaOH$ :-

Given mass = 90.0 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{90.0\ g}{39.997\ g/mol}$

$Moles\ of\ NaOH= 2.2502\ mol$

Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.

The expression for the molarity, according to its definition is shown below as:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Where, Volume must be in Liter.

It is denoted by M.

Given, Volume = 3.00 L

So,

$Molarity=\frac{2.2502\ mol}{3.00\ L}=0.75\ M$

Final concentration of NaOH = 0.75 M

5 0

2 years ago

A 25.00 mL sample of vinegar was titrated with 39.27 mL of 0.4293 M NaOH. Calculate the concentration of acetic acid in the vine

QveST [7]

Answer:

0.6743 M

Explanation:

HC₂H₃O₂ + NaOH → NaC₂H₃O₂ + H₂O

First we calculate how many NaOH moles reacted, using the definition of molarity:

Molarity = moles / volume

moles = Molarity * volume

0.4293 M * 39.27 mL = 16.86 mmol NaOH

One NaOH moles reacts with one acetic acid mole, so the vinegar sample contains 16.86 mmoles of acetic acid as well.

Finally we calculate the concentration (molarity) of acetic acid:

16.86 mmol HC₂H₃O₂ / 25.00 mL = 0.6743 M

4 0

2 years ago