The answer would be 833.7
Answer:
<h2>
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Explanation:
According to hooks law "provide the elastic limit of an elastic material is not exceeded the extension e is directly proportional to the applied force F"
where F= applied force
k= spring constant
e= extension
Given data
length of string l = 16cm
extension e = 20-16= 4cm
applied force = 5N
we need t o first calculate the spring constant k
apply the formula
we can now calculate the extension of the string when supporting a 6N weight
The length of the string when supporting a 6N weight is
<em>COMMENT </em><em>:According to the analysis an extra weight of 1N will cause add 0.8cm to the length of the string</em>
Answer:
A) { + } Ge-Se { -}
B) { + } Ge-Br { - }
C) { - } Br-Se { + }
Explanation:
The (-)ive sign shall be placed for the atom with higher electronegativity, while the other atom will be electropositive.
a) Electronegativity of Ge = 2.01
Electronegativity of Se = 2.55
{ + } Ge-Se { -}
b) Electronegativity of Ge = 2.01
Electronegativity of Br = 2.95
{ + } Ge-Br { - }
c) Electronegativity of Br = 2.95
Electronegativity of Se = 2.55
{ - } Br-Se { + }
1.hydrogen
2.carbon
3.argon
4.titanium
5.cesium
Answer:
Time=345.7 min
Explanation:
It is an example for Faraday's first law of Electrolysis
It states that the amount of substance deposited is directly proportional to the amount of electricity passed.
W=Zit
Z=E/96500
W= E it/96500
And E=58.7(molar mass of Ni)/2(charge on Ni)=29.3
t=W96500/E i
= 29.6x96500/29.3x4.7
= 20742.1 sec
=345.7 min
