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2 years ago

Three equal ratios to 6/7

Mathematics

2 answers:

Yanka [14]2 years ago

5 0

<span>1. 12/14 , 2. 18/21 ,3. 24/28
hope this helps</span>

Rashid [163]2 years ago

4 0

12/14 , 18/21 , 24/28

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3 years ago

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A survey finds that 55 people out of 170 favor increasing property taxes to help pay for a new library. If this data is used to

Aloiza [94]

Answer: B. 0.036

Step-by-step explanation:

Formula for standard error :

$SE=\sqrt{\dfrac{p(1-p)}{n}}$

, where p = Population proportion and n= sample size.

Let p be the population proportion of the people who favor new taxes.

As per given , we have

n= 170

$p=\dfrac{55}{170}\approx0.324$

Substitute these values in the formula, we get

$SE=\sqrt{\dfrac{0.324(1-0.324)}{170}}\\\\=\sqrt{0.00129}\\\\=0.0359165699921\approx0.036$

Hence, the standard error of the estimate is 0.036.

∴ The correct answer is OPTION B. 0.036

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3 years ago

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Stels [109]

I am pretty sure the answer is B

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3 years ago

Find the measure of DA

Keith_Richards [23]

Answer:

Step-by-step explanation:

First, find x

set your formula up as 3x+5=6x-10, since AB and DC are the same length.

This means x = 5

Now substitute 5 for x in the line DA

4x-5

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2 years ago

Peter's farm has 160 meters of fencing, and he wants to fence a rectangular field thatborders a straight river. He needs no fenc

Likurg_2 [28]

ANSWER

3200 m²

EXPLANATION

Peter wants to build a fence around a rectangular field, except for one side because the river is there,

So, the total perimeter of the fence is,

$P=W+W+L=2W+L$

And this is equal to 160 m. Solving for L,

$160=2W+L\text{ }\Rightarrow\text{ }L=160-2W$

The area of this field is,

$A=WL$

Replace L with the expression we found from the perimeter,

$A=W(160-2W)=160W-2W^2$

The area is given by a quadratic function whose leading coefficient is negative, which means that the graph is a downward parabola and, therefore, the vertex is the maximum value of the area.

The x-coordinate of the vertex is given by,

$f(x)=ax^2+bx+c\text{ }\Rightarrow\text{ }x_{vertex}=\frac{-b}{2a}$

In this case, x is W, a = -2, and b = 160, so the width of the field for the maximum area is,

$W_{vertex}=\frac{-160}{2(-2)}=\frac{160}{4}=40m$

And the length when W = 40 is,

$L=160-2W=160-2\cdot40=160-80=80m$

And the area is,

$A=WL=40m\cdot80m=3200m^2$

Hence, the largest area of Peter's farm that can be fenced is 3200 square meters.

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8 months ago