What is the orbital hybridization of a central atom that has one lone pair and bonds to:
1 answer:
is the orbital hybridization of a central atom that has one lone pair and bonds to three other atoms.
In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.
For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.
Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.
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The equilibrium constant for the reaction is 0.00662
Explanation:
The balanced chemical equation is :
2NO2(g)⇌2NO(g)+O2(g
At t=t 1-2x ⇔ 2x + x moles
The ideal gas law equation will be used here
PV=nRT
here n= =
= density
P = density is 0.525g/L, temperature= 608.15 K, P = 0.750 atm
putting the values in reaction
0.75 =
M = 34.61
to calculate the Kc
Kc=
x M NO2 +
M NO+
M O2
Putting the values as molecular weight of NO2, NO,O2
34.61=
x= 0.33
Kc=
putting the values in the above equation
Kc = 0.00662