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Sphinxa [80]
2 years ago
9

What is the orbital hybridization of a central atom that has one lone pair and bonds to:

Chemistry
1 answer:
nirvana33 [79]2 years ago
5 0

sp^3  is the orbital hybridization of a central atom that has one lone pair and bonds to three other atoms.

<h3>What is orbital hybridization?</h3>

In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.

For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.

Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.

Learn more about Hybridization

brainly.com/question/22765530

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When a sample of ca(s) loses 1 mole of electrons in a reaction with a sample of o2(g) the oxygen?
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The reaction involved in present case is:

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What is the resistance of a 150 W lightbulb connected to a 24 V voltage source?
Luda [366]

Answer:

3.84 Ω

Explanation:

From the question given above, the following data were obtained:

Electrical power (P) = 150 W

Voltage (V) = 24 V

Resistance (R) =?

P = IV

Recall:

V = IR

Divide both side by R

I = V/R

P = V/R × V

P = V² / R

Where:

P => Electrical power

V => Voltage

I => Current

R => Resistance

With the above formula (i.e P = V²/R), we can calculate resistance as illustrated below:

Electrical power (P) = 150 W

Voltage (V) = 24 V

Resistance (R) =?

P = V²/R

150 = 24² / R

150 = 576 / R

Cross multiply

150 × R = 576

Divide both side by 150

R = 576 / 150

R = 3.84 Ω

Thus, the resistance is 3.84 Ω

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