Answer:
Kc of the reaction is 0.9375
Explanation:
Step 1: Data given
Moles of SO2 = 0.40 moles
Moles of O2 = 0.60 moles
Volume = 1.00 L
After the reactio we find 0.30 moles SO3
Step 2: The balanced equation
2 SO2(g) + O2(g) ⇔ 2SO3(g)
Step 3: Calculate Kc
Kc = [SO3]² / ([SO2]²[O2])
Kc = 0.30² / (0.40²*0.60)
Kc = 0.9375
Kc of the reaction is 0.9375
Answer:
The given hydrocarbon is Ethylene Glycol
Answer:
The calculated concentration of HCl will be less than actual.
Explanation:
Suppose during titration, the <em>HCl</em> was taken in burette and the <em>NaOH</em> in the volumetric flask.
Now we will use equivalence formula for the calculation of concentration of HCl.
![N_{1} V_{1} = N_{2} V_{2}](https://tex.z-dn.net/?f=N_%7B1%7D%20V_%7B1%7D%20%3D%20N_%7B2%7D%20V_%7B2%7D)
Where L.H.S is for hydrochloric acid and R.H.S is for sodium hydroxide. The terms N and V represent normality and volume respectively.
If we calculate for
![N_{1} = \frac{N_{2}V_{2} }{V_{1} }](https://tex.z-dn.net/?f=N_%7B1%7D%20%3D%20%5Cfrac%7BN_%7B2%7DV_%7B2%7D%20%7D%7BV_%7B1%7D%20%7D)
We see that if the volume of the HCl is greater then the concentration of the HCl will be reduced.
The precision of a tool can affect the measurement's accuracy. how specific the measurement can get (if it goes to the tenths place, hundredths, etc) can also affect the accuracy.