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serg [7]
2 years ago
4

In a two slit experiment the third bright fringe away from the central fring eis observed at an angle of 8 if the wavelength of

the light is 490 nm what is the distance bewteen thetwo slits?
Physics
1 answer:
Olegator [25]2 years ago
3 0

The distance between two slit is 0.00149 mm, when In a two slit experiment the third bright fringe away from the central fringe is observed at an angle of 8 if the wavelength of the light is 490 nm.

<h2>Double slit experiment: what is it?</h2>

A light beam is directed at a wall that has two vertical slits in the double-slit experiment. The resulting pattern is captured on a photographic plate after the light has passed through the slits. A single line of light that is aligned with the open slit is visible when one slit is covered.

The equation provides the positions of the interference fringes:

In the case of bright interference fringes, they appear at d × siny = n × λand nth bright appear at d × siny = (n +1) × λ respectively.

<h2>calculating the separation of two slits:</h2>

In a double slit experiment, the prerequisite for constructive interference is: d × siny = n × λ

Where, number of the fringe (n)  = 3

The wavelength of light (λ) = 490 nm = 4.90 × 10^{-7} m

d is the distance between two slits.

Let's now determine the response:

d = \frac{n}{siny } × λ

d = \frac{3 * 4.9  *  10^{-7} }{sin(8 )}

d = 0.00149 mm  

Thus, the distance between two slits is 0.00149 mm.

To know  more about double slit experiment visit: brainly.com/question/28108126

#SPJ4

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