The distance between two slit is 0.00149 mm, when In a two slit experiment the third bright fringe away from the central fringe is observed at an angle of 8 if the wavelength of the light is 490 nm.
<h2>Double slit experiment: what is it?</h2>
A light beam is directed at a wall that has two vertical slits in the double-slit experiment. The resulting pattern is captured on a photographic plate after the light has passed through the slits. A single line of light that is aligned with the open slit is visible when one slit is covered.
The equation provides the positions of the interference fringes:
In the case of bright interference fringes, they appear at d × siny = n × λand nth bright appear at d × siny = (n +1) × λ respectively.
<h2>calculating the separation of two slits:</h2>
In a double slit experiment, the prerequisite for constructive interference is: d × siny = n × λ
Where, number of the fringe (n) = 3
The wavelength of light (λ) = 490 nm = 4.90 ×
m
d is the distance between two slits.
Let's now determine the response:
d =
× λ
d = 
d = 0.00149 mm
Thus, the distance between two slits is 0.00149 mm.
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