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wariber [46]
3 years ago
13

2 Polnis

Physics
1 answer:
Marta_Voda [28]3 years ago
7 0

Answer:

Oprion A

The length of time over which the conditions are measured

Explanation:

Weather captures the daily atmospheric conditions over a short duration hence it is short-term. Climate is the average of weather and covers a longer duration hence long-term. Therefore, what differentiatea these two is the length of time over which the conditions are measured.

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8. There are different characteristics for each of the states of matter. Which statement
Ahat [919]

Answer:

a. Temperatures increase can change a solid to a liquid, but cannot change a liquid to a solid

b. The particles in a solid are much closer together than the particles in a liquid.

Explanation:

Any material expands when heated and contracts when cooled. So, when a body is heated to a particular temperature, it starts melting and changes into a liquid.

As the material expands the distance between the atoms or molecules increases and it will become a liquid. So it can move around the material. It doesn't become solid on further heating. But water is an exception where it contracts when heated from 0° to 4° C.

In solids, these atoms or molecules are closely packed. It is rigidly fixed.

The solid, as well as the liquid, has a definite volume, but the liquid does not have a definite shape.

5 0
4 years ago
Two point charges of +2.0 μC and -6.0 μC are located on the x-axis at x = -1.0 cm and x = +2.0 cm respectively. Where should a t
lyudmila [28]

Answer:

  x = -3 cm

Explanation:

The electrical potential is the sum of the potentials of each charge

       V = k ∑ q_{i} / r_{i}

let's apply this to our case where the potential is V = 0 for x = 0

         0 = k (q₁ / (x₁-0) + q₂ / (x₂-0) + q₃ / (x₃-0))

in our case

q₁ = + 2.0 10⁻⁶ C

q₂ = - 6.0 10⁻⁶ C

q₃ = + 3.0 10⁻⁶ C

x₁ = -1.0 cm = 1.0 10⁻² m

x₂ = +2.0 cm = 2.0 10⁻² m

we substitute in the equation

          0 = k (2 10⁻⁶ / 1 10⁻² - 6 10⁻⁶ / 2 10⁻² + ​​3 10⁻⁶ / x)

          3 10⁻⁶ / x = 2 10⁻⁴ - 3 10⁻⁴

          3 10⁻⁶ / x = -1 10⁻⁴

           x = - 3 10⁻² m

           x = -3 cm

7 0
3 years ago
A 400.0 kg storage box is held 10 m above ground by a forklift. What is its gravitational potential energy? (PE = mgh)
Kobotan [32]

Answer:

The gravitational potential energy (PE) of a particle or a system of particles is a form of energy that exists due to its position. Mathematically, it is expressed as the product of mass, gravitational acceleration, and the vertical displacement.

Explanation:

Given data:

Mass of the storage box, m = 400.0 \ kg

Height, h = 10 \ m

The gravitational potential energy of the storage box can be expressed as,

PE = mgh

PE = 400.0 \times 9.80 \times 10

PE = 39200 \ \rm J.

8 0
4 years ago
Read 2 more answers
Es muy común que cuando se viaja hacia un río o lago se juegue "ranita", el cual consiste en lanzar una piedra horizontalmente h
shutvik [7]

Answer:

a) La piedra es lanzada desde una altura de 0,785 metros.

b) La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.

Explanation:

a) Dado que la piedra es lanzada horizontalmente, tenemos que la piedra experimenta un movimiento horizontal a velocidad constante y uno vertical uniformemente acelerado debido a la gravedad. La altura de la que fue lanzada la piedra se puede determinar mediante la siguiente ecuación cinemática:

y = y_{o}+v_{o,y}\cdot t +\frac{1}{2}\cdot g\cdot t^{2} (1)

Donde:

y - Altura final, medida en metros.

y_{o} - Altura inicial, medida en metros.

v_{o,y} - Componente vertical de la velocidad inicial, medida en metros por segundo.

t - Tiempo, medido en segundos.

g - Aceleración gravitacional, medida en metros por segundo cuadrado.

Si sabemos que y = 0\,m, v_{o,y} = 0\,\frac{m}{s}, t = 0,4\,s y g = -9,807\,\frac{m}{s^{2}}, entonces la altura inicial de la piedra es:

y_{o} = y-v_{o,y}\cdot t -\frac{1}{2}\cdot g\cdot t^{2}

y_{o} = 0\,m-\left(0\,\frac{m}{s} \right)\cdot (0,4\,s)-\frac{1}{2}\cdot \left(-9,807\,\frac{m}{s^{2}} \right) \cdot (0,4\,s)^{2}

y_{o} = 0,785\,m

La piedra es lanzada desde una altura de 0,785 metros.

b) Ahora, obtenemos el componente horizontal de la velocidad inicial a partir de la siguiente ecuación cinemática:

v_{o,x} = \frac{x-x_{o}}{t} (2)

Donde:

x_{o}, x - Posiciones horizontales iniciales y finales, medidas en metros.

t - Tiempo, medido en segundos.

Si tenemos que x_{o} = 0\,m, x = 2,5\,m y t = 0,4\,s, entonces el componente horizontal de la velocidad inicial es:

v_{o,x} = \frac{2,5\,m-0\,m}{0,4\,s}

v_{o,x} = 6,25\,\frac{m}{s}

La piedra es lanzada con una velocidad inicial de 6,25 metros por segundo.

4 0
3 years ago
The melting point of a substance is the same as its _____ point.
kirza4 [7]

Answer:

Boiling point

Explanation:

5 0
3 years ago
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