Jack and Jill have a pail of water. Which action will cause the molecules of water to move faster?

Operating speed of an automatic washing machine is 5.5 rad s-1. After loading dirty clothes and pressing a start button, the tub

AlekseyPX

The equations for rotary motion is based on motion in a circular path

a) Time taken by clothes to come up to speed during washing is approximately 1.325 s

b) The tub turns approximately 24.016 revolutions in the 20.0 s interval

Reasons:

Known parameter are;

Operating speed of an automatic washing machine = 5.5 rad·s⁻¹

Average angular acceleration of the washing machine, α = 4.15 rad·s⁻²

Angular speed in the spin-dry mode, ω = 6.0 revolution per second

Time it takes to reach angular speed in spin-dry mode = 7.0 s

a) The relationship between angular acceleration and time are;

$\alpha = \dfrac{\Delta \omega}{\Delta t}$ , $\Delta t = \dfrac{\Delta \omega}{\alpha}$

Where;

Δω = ω₂ - ω₁ = 5.5 rad·s⁻¹

Δt = The time it takes to accelerate

Therefore;

$\Delta t = \dfrac{5.5 \ rad\cdot s^{-1}}{4.15 \ rad \cdot s^{-2}} \approx 1.325 \ s$

The time it takes for the clothes to come up to speed during the washing mode, Δt ≈ 1.325 s

b) The angular acceleration of the spin-dry mode is given as follows;

6 revolutions per second = 2·π ×6 rad per second = 12·π rad/s

$\alpha = \dfrac{\Delta \omega}{\Delta t}$

The acceleration during spin up

$\therefore \alpha = \dfrac{12 \cdot \pi }{7.0} \ rad \cdot s^{-2} \approx 5.39 \ rad \cdot s^{-2}$

The acceleration during slowing down;

$\therefore \alpha = \dfrac{12 \cdot \pi }{13.0} \ rad \cdot s^{-2} \approx 2.9 \ rad \cdot s^{-2}$

The angle turned in the 20.0 second interval is therefore;

$\dfrac{1}{2} \times 5.39 \times 7^2 + 12 \cdot \pi \times 7-\dfrac{1}{2} \times 2.9 \times 13^2 \approx 150.9$

The angle turned in the 20.0 s is approximately 150.9 radians

$Number \ of \ revolutions \ =\dfrac{\theta}{2 \cdot \pi}$

Therefore;

$Number \ of \ revolutions \ in \ 20.0 \ s =\dfrac{150.9 }{2 \cdot \pi} \approx 24.016$

The number of revolutions of the tub in the 20.0 s interval is approximately 24.016 revolutions

Learn more about constant angular acceleration here:

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What is the cause of atmospheric pressure.

marusya05 [52]

Explanation:

hope it's help you ok have a good day

6 0

3 years ago

If a force of 10 n is applied to an object with a mass of 1kg the object will accelerate at

givi [52]

We Know, F = m*a
Here, F = 10 N
m = 1 Kg

Substitute their values in the equation,
10 = 1 * a
a = 10/1
a = 10

So, your final answer & the acceleration of the object would be 10 m/s²

Hope this helps!

3 0

3 years ago

At what distance will a 45 W lightbulb have the same apparent brightness as a 130 W bulb viewed from a distance of 35 m ? (Assum

Sloan [31]

Answer:

20.6 m

Explanation:

P₁ = Power of first bulb = 45 W

P₂ = Power of second bulb = 130 W

r₁ = distance from the first bulb

r₂ = distance from the second bulb = 35 m

Using the equation

$\frac{P_{1}}{r_{1}^{2}} = \frac{P_{2}}{r_{2}^{2}}$

Inserting the values

$\frac{45}{r_{1}^{2}} = \frac{130}{35^{2}}$

r₁ = 20.6 m

5 0

4 years ago

A tennis ball is thrown upwards from the edge of a cliff with a speed of 10\,\dfrac{\text m}{\text s}10 s m 10, start fraction

tresset_1 [31]

Answer:

5.1m

Explanation:

Given the following parameters

Speed v = 10m/s

Time = 3.0s

Required

Displacement of the tennis ball

Using the equation of motion

v² =u²-2gh (g i s negative due to upward motion of the ball)

Substitute the given values into the expression above;

0² = 10²-2(9.8)h

0 = 100-19.6h

19.6h = 100

h = 100/19.6

h= 5.1m

Hence the displacement of the ball is 5.1m

5 0

3 years ago