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denis-greek [22]
4 years ago
15

NEED ASAP 5 complete sentences explaining how burning fossil fuels could potentially affect acid rain in your community and how

we could reduce its contributions to acid rain. Your paragraph should have an introduction and conclusion like an essay.
Physics
1 answer:
Rasek [7]4 years ago
7 0
How do fossil fuels lead to acid rain? How can we stop it? Well, that's what we are going to uncover today! Fossil fuels contain horrible things that contribute to air pollution. Pollutants in the air are one of the main ingredients to acid rain. So, that's how fossil fuels contribute to acid rain. But how can we stop it? We could cut down on fossil fuels. And since they are non-renewable, we need to stop anyway...so why not now. The problem is that most of America are using fossil fuels. But, one community at a time could change this. In conclusion, fossil fuels can lead to acid rain by polluting the air and we can stop this by putting a stop on fossil fuels. 
Hope this helped! (sorry i took so long)
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Find the least frequency of incident light that will knock electrons out of the surface of a metal with a work function of 3eV.​
mixer [17]

Answer:

The frequency must be: 725\,\,10^{12} \,Hz

Explanation:

If the work function of the metal (\phi) is 3 eV, then we can use the formula for the kinetic energy of an ejected electron:

KE= h*f-\phi

considering for the minimum KE = 0, and using the Plank constant h in eV s as: 4.14 * 10 ^(-15) eV s, to solve for the frequency:

h*f=\phi\\4.14*10^{-15} * f = 3\\f=3*10^{15}  /4.14\,\,\frac{1}{s} \\f=725\,10^{12} \,Hz

3 0
3 years ago
Give an example of forces adding together
hammer [34]
Two forces are magnets
5 0
3 years ago
If you have 240.0 mL of water at 25.00 °C and add 100.0 mL of water at 95.00 °C, what is the final temperature of the mixture? U
Rus_ich [418]

<u>Answer:</u> The final temperature of the mixture is 45.6°C

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of water = 1 g/mL

  • <u>When volume is 240.0 mL</u>

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{240.0mL}\\\\\text{Mass of water}=(1g/mL\times 240.0mL)=240g

  • <u>When volume is 100.0 mL</u>

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{100.0mL}\\\\\text{Mass of water}=(1g/mL\times 100.0mL)=100g

When two water solutions at different temperature are mixed, the amount of heat released by water present at higher temperature will be equal to the amount of heat absorbed by water present at lower temperature..

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of water solution 1 = 240 g

m_2 = mass of water solution 2 = 100 g

T_{final} = final temperature = ?°C

T_1 = initial temperature of water solution 1 = 25°C

T_2 = initial temperature of water solution 2 = 95°C

c = specific heat of water= 4.186 J/g°C

Putting values in equation 1, we get:

240\times 4.186\times (T_{final}-25)=-[100\times 4.186\times (T_{final}-95)]\\\\T_{final}=45.6^oC

Hence, the final temperature of the mixture is 45.6°C

7 0
3 years ago
Read 2 more answers
If a triangle is a right triangle, then the other two angles must be acute. true or false
skelet666 [1.2K]
That depends on which angle you picked first, because that determines
which angles "the other two" are.

If you picked the right angle (90°) first, before you asked the question,
then the other two are acute angles, and they're also complementary
5 0
4 years ago
Earning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement
lana [24]

Answer:

the work done by the 30N force is 4156.92 J.

For this problem, they don´t ask you to determine the work of the total force applied in the block. They only want the work done for the force of 30N, with an angle of 30º respectively of the displacement and a traveled distance of 160m. So:

W=F·s·cos(α)=30N·160m·cos(30º)=4156.92J

8 0
3 years ago
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