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3 years ago

2ax-15=2(x+5)+5(x-1)

1 answer:

5 0

Perform the indicated multiplication:

2ax - 15 = 2x + 10 + 5x - 5

Group x terms together: 7x - 2ax = 5 - 15
x(7-2a) = - 10
-10
x = ----------
7-2a

Here, a cannot be 3.5, because the denominator 7-2a would be zero.

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In a group of 24 people, 10 study

Minchanka [31]

Answer:

n = 24

p(a) = 10/24

p(b) = 15/24

[ p(a) + p(b) - [p(a) ×p(b)] ] -1 = answer

[ 35/24 - 6/24 ] -1 = 39/24 - 24/24 = 5/24

8 0

2 years ago

Read 2 more answers

What is the smallest 6 digit palindrome that is divisible by 99

Scorpion4ik [409]

Answer:

108801

Step-by-step explanation:

6-digit palindrome is the number n the form of:

xyzzyx

This is divisible by 11 by default as the sum of the digits in odd placed is same as sum of the number in even places (remember the divisibility rule by 11):

x + z + y = y + z + x

Now, in order to be divisible by 99, the number must be divisible by 11 and 9.

According to divisibility rule by 9 the sum of all digits must be divisible by 9. You can see In our case we need to have (the minimum):

x + y + z = 9

The smallest number we could get is when x is minimum, y is minimum, so:

x = 1, y = 0, then y = 8

The number we get is:

108801

Proof:

108801/99 = 1099

4 0

2 years ago

Read 2 more answers

The stadium has 53,000 seats seats sell for $42 in section 8 $36 in section B $30 in section C the number of seats in this in se

Zielflug [23.3K]

Answer:

Section A = 26,500 seats

Section B = 14,900 seats

Section C = 11,600 seats

Step-by-step explanation:

Total seats = 53,000

Total revenue = 1,997,400

Section A seat = $42

Section B seat = $36

Section C seat = $30

The number of seats in this in section A equals the total number of seats in section BNC

A = B + C

A + B + C = 53,000 (1)

42A + 36B + 30C = 1,997,400 (2)

Substitute A = B + C into (1)

A + B + C = 53,000

B + C + B + C = 53,000

2B + 2C = 53,000

2(B + C ) = 53,000

B + C = 53,000 / 2

= 26,500

B + C = 26,500 (3)

Substitute B + C = 26,500 into (2)

42A + 36B + 30C = 1,997,400

Recall,

A = B + C

42( 26,500) + 36B + 30C = 1,997,400

1,113,000 + 36B + 30C = 1,997,400

36B + 30C = 1,997,400 - 1,113,000

36B + 30C = 884,400. (4)

Multiply (3) by 30

B + C = 26,500 × 30

30B + 30C = 795,000 (5)

36B + 30C = 884,400 (4)

Subtract (5) from (4) to eliminate C

36B - 30B = 884,400 - 795,000

6B = 89,400

B = 89,400/6

= 14,900

B = 14,900

From (3)

B + C = 26,500

C = 26,500 - B

= 26,500 - 14,900

= 11,600

A = B + C

= 14,900 + 11,600

= 26,500

Section A = 26,500 seats

Section B = 14,900 seats

Section C = 11,600 seats

8 0

2 years ago

I need to know the surface area of these

anastassius [24]

9514 1404 393

Answer:

245 cm²

Step-by-step explanation:

The surface area of a cone is given by ...

SA = πr(r +s) . . . . where r is the radius, and s is the slant height

Filling in the given values, we have ...

SA = (3.14)(3 cm)(3 cm +23 cm) = (3.14)(3)(26) cm² ≈ 245 cm²

The surface area of the cone is about 245 cm².

6 0

3 years ago

A veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses

Licemer1 [7]

Answer:

Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

Step-by-step explanation:

We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.

So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = average age of the random sample of horses with colic = 12 yrs

$\mu$ = average age of all horses seen at the veterinary clinic = 10 yrs

$\sigma$ = standard deviation of all horses coming to the veterinary clinic = 8 yrs

n = sample of horses = 60

So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P( $\bar X$ $\geq$ 12)

P( $\bar X$ $\geq$ 12) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{12-10}{\frac{8}{\sqrt{60} } }$ ) = P(Z $\geq$ 1.94) = 1 - P(Z < 1.94)

= 1 - 0.97381 = 0.0262

Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.

4 0

3 years ago