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2 years ago

2ax-15=2(x+5)+5(x-1)

1 answer:

5 0

Perform the indicated multiplication:

2ax - 15 = 2x + 10 + 5x - 5

Group x terms together: 7x - 2ax = 5 - 15
x(7-2a) = - 10
-10
x = ----------
7-2a

Here, a cannot be 3.5, because the denominator 7-2a would be zero.

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Quadrilateral BCDE is a square. What is mZDCF?

o-na [289]

Answer:

4 squares make up a triangle so divide the degrees if the square by the triangle.

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2 years ago

Hiya !

Aleksandr [31]

Answer:

root 25

Step-by-step explanation:

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1 year ago

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In the last six months, Sonia's family used 529, 499, 651, 652, 1,163, and 310 minutes on their cell phone plan. To save money,

Tresset [83]

Answer:

They went over their goal for the last six months by 34 minutes per month.

Step-by-step explanation:

Mean of a data-set:

The mean of a data-set is the sum of all values in the data-set divided by the size of the data-set.

529, 499, 651, 652, 1,163, and 310 minutes on their cell phone plan.

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$M = \frac{529+499+651+652+1163+310}{6} = 634$

By how many minutes did they go over their goal in the last six months?

The mean was of 634 minutes, and they wanted to keep it below 600. So

634 - 600 = 34

They went over their goal for the last six months by 34 minutes per month.

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2 years ago

Plot the points on a graph.A(0,0);B(0,2);C(2,2);D(2,0). Join AB, BC,CD and AD. What is the figure formed? Find the area of the f

tia_tia [17]

$\large \green{ \underline{ \blue{ \boxed{\bf{ \red{Given -}}}}}}$

Four points which lie at (0,0) ; (0,2) ; (2,2) ; (2,0)

$\large \green{ \underline{ \blue{ \boxed{\bf{ \red{To \: Find-}}}}}}$

What is the figure formed?What is the area of the figure?

$\large \green{ \underline{ \blue{ \boxed{\bf{ \red{Solution-}}}}}}$

The given points lie on graph as per the order given in the attachment.

Which shape?

As the points lie 2 units apart from their adjacent sides. It can be a square or rhombus.

The opposite pairs of sides are also parallel to each other. The adjacent sides of the figure formed are also perpendicular to each other.

<u>Hence! the figure formed is a square.</u>

What is the area?

$\large{\sf{ \longmapsto Area_{(square)} = s \times s}}$

$\large{\sf{ \longmapsto Area_{(square)} = {s}^{2} }}$

$\large{\sf{ \longmapsto Area_{(square)} = {(2)}^{2} }}$

$\large{\sf{ \longmapsto Area_{(square)} = 4 \: sq. \: units}}$

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1 year ago

]solomon needs to justify the formula for the arc length of a sector. which expression best completes this argument? the circumf

Anna35 [415]

Answer:

$\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}$ best completes this argument

Step-by-step explanation:

Circumference of circle = $\pi \cdot d$

Where d is the diameter of circle

We are given that if equally sized central angles, each with a measure of n°, are drawn, the number of sectors that are formed will be equal to $\frac{360^{\circ}}{n^{\circ}}$

So, Number of sectors = $\frac{360^{\circ}}{n^{\circ}}$

The arc length of each sector is the circumference divided by the number of sectors

$\Rightarrow \frac{\pi \cdot d}{\frac{360^{\circ}}{n^{\circ}}}$

Diameter d = 2r (r = radius)

$\Rightarrow \frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}$

Option b is true

Hence $\frac{2 \pi r}{\frac{360^{\circ}}{n^{\circ}}}$ best completes this argument

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2 years ago