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KATRIN_1 [288]
2 years ago
14

In a physics lab, you measure the vibrational-rotational spectrum of hcl. the estimated separation between absorption peaks is:_

________-
Physics
1 answer:
BlackZzzverrR [31]2 years ago
8 0

The appropriate value in blank given is Δf = 5.5 x 10^{11} Hertz.

We have vibrational - rotational spectrum Hydrochloric Acid.

We have to investigate the estimated separation between absorption peaks and fill the blank.

<h3>What is vibrational - rotational spectrum ?</h3>

Rotational–vibrational spectroscopy is a branch of molecular spectroscopy. It deals with the infrared and Raman spectra of molecules in the gaseous phase.

According to the question -

The estimated separation between absorption peaks in the vibrational-rotational spectrum of HCl is denoted by Δf and is equal to -

Δf = 5.5 x 10^{11} Hertz

Hence, the appropriate value in blank given is Δf = 5.5 x 10^{11} Hertz.

To learn more about vibrational-rotational spectrum, visit the link below-

brainly.com/question/18403840

#SPJ4

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Describe the relationship between the potential and kinetic energies of the tennis ball as it travels the length of the roller c
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If we neglect frictional force, the total mechanical energy of the ball is conserved.
The total mechanical energy of the ball is the sum of its kinetic energy K and its potential energy U:
E=K+U
where the kinetic energy depends on the speed v of the ball: 
K= \frac{1}{2} mv^2 
while the potential energy depends on the height h at which the ball is:
U=mgh

As the ball travels along the roller coaster, there is a continuous conversion between kinetic and potential energy, because the total mechanical energy E has always the same value. Therefore, when the ball goes on top of a hill, its height h increases and its potential energy U increases as well, while the speed v decreases and K decreases. Vice-versa, when the ball reaches the bottom of a hill, its height h decreases and therefore the potential energy U decreases, while the speed v increases and therefore the kinetic energy K of the ball increases as well.
8 0
4 years ago
A heat recovery system​ (HRS) is used to conserve heat from the surroundings and supply it to the Mars Rover. The HRS fluid loop
Annette [7]

Answer: Volume of Freon = 12.23.10^{3}L

Explanation: First, the temperatures have to be in the same unit, so all the tmeperatures is transformed into Kelvin:

T₁ = 192K

T₂ = \frac{5}{9}. (F - 32)+273.15

T₂ = \frac{5}{9}. (- 65 - 32)+273.15

T₂ = 219.26K.

Second, BTU is an unit of energy. It can be transformed into Joules by the relation 1BTU = 1055.06J.

Q = 1055.06 . 46.9 = 49482.314J

The letter Q represents Heat and is calculated as Q = m.Cp.ΔT, where:

m is mass of the element;

Cp is the heat capacity specific for each element;

ΔT is the difference between the final and initial temperature;

Third, it will be needed the properties of the Freon:

Freon (CF2Cl2) = 120.91g/mol; Cp = 74J/mol.K; ρ = 1.49kg/m³

Fourth, we calculate the mass of Freon necessary for the remove of 46.9BTU of energy from the system:

Q = m.Cp.ΔT

m=\frac{Q}{c(T-T_{0} )}

m = \frac{49482.314}{74(219.26-192)}

m = 18228.214g or m=18.228Kg

Fifth, using the density of Freon, Volume can be found

ρ = \frac{m}{V}

V = m / ρ

V = 18.228 / 1.49

V = 12.23m³

As SI for density is Kg/m³, the volume found is in m³.

Cubic meters is related to Liters as the following: 1m³=1000l.

So, volume of Freon = 12.23.10^{3}L

The volume of Freon needed is 12.23.10^{3}L.

7 0
3 years ago
A pole AB of length 10.0m and weight 600N has its center of gravity 4.0m from the end A, and lies on horizontal ground .Calculat
postnew [5]

Answer:

The force required to begin to lift the pole from the end 'A' is 240 N

Explanation:

The given parameters for the pole AB are;

The length of the pole, l = 10.0 m

The weight of the pole, W = 600 N ↓

The distance of the center of gravity of the pole from the side 'A' = 4.0 m

Let 'F_A' represent the force required to begin to lift the pole from the end 'A' and let a force applied in the upwards direction be positive

For equilibrium, the sum of moment about the point 'B' = 0, therefore, taking moment about 'B', we have

F_A × 10.0 m - W × 4.0 m = 0

∴ F_A × 10.0 m = W × 4.0 m = 600 N × 4.0 m

F_A × 10.0 m = 600 N × 4.0 m

∴  F_A = 600 N × 4.0 m/(10.0 m) = 240 N

The force required to begin to lift the pole from the end 'A', F_A = 240 N.

8 0
3 years ago
A rocket traveling at 80 m/s is accelerated uniformly to 152 m/s over a 18 s interval. What is its displacement during this time
IgorLugansk [536]

Recall that with constant acceleration,

x_f-x_i=\dfrac{v_i+v_f}2t

where x_f-x_i is the rocket's displacment, v_i is its initial velocity, v_f its final velocity, and t is time. So

x_f-x_i=\dfrac{80\frac{\mathrm m}{\mathrm s}+152\,\frac{\mathrm m}{\mathrm s}}2(18\,\mathrm s)=2088\,\mathrm m

or just 2100 m if taking significant digits into account.

8 0
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A point charge q1 is held stationary at the origin. A second charge q2 is placed at point a, and the electric potential energy o
Brrunno [24]

The electric potential energy of the pair of charges when the second charge is at point b is 7.3 x 10⁻⁸ J.

<h3>Electric potential energy</h3>

When work is done on a positive test charge to move it from one location to another, potential energy increases and electric potential increases.

The electric potential energy between the charges when the second charge is at point b is calculated as follows;

ΔU = -w

Ui - Uf = w

Uf = Ui - w

where;

Uf is the final potential energy

Ui is the initial potential energy

w is the work done by the force

Uf = 5.4 x 10⁻⁸ J - (-1.9 x 10⁻⁸J)

Uf = 5.4 x 10⁻⁸ J + 1.9 x 10⁻⁸ J

Uf = 7.3 x 10⁻⁸ J

Thus, the electric potential energy of the pair of charges when the second charge is at point b is 7.3 x 10⁻⁸ J.

Learn more about electric potential energy here: brainly.com/question/14306881

#SPJ1

7 0
2 years ago
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