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KATRIN_1 [288]
2 years ago
14

In a physics lab, you measure the vibrational-rotational spectrum of hcl. the estimated separation between absorption peaks is:_

________-
Physics
1 answer:
BlackZzzverrR [31]2 years ago
8 0

The appropriate value in blank given is Δf = 5.5 x 10^{11} Hertz.

We have vibrational - rotational spectrum Hydrochloric Acid.

We have to investigate the estimated separation between absorption peaks and fill the blank.

<h3>What is vibrational - rotational spectrum ?</h3>

Rotational–vibrational spectroscopy is a branch of molecular spectroscopy. It deals with the infrared and Raman spectra of molecules in the gaseous phase.

According to the question -

The estimated separation between absorption peaks in the vibrational-rotational spectrum of HCl is denoted by Δf and is equal to -

Δf = 5.5 x 10^{11} Hertz

Hence, the appropriate value in blank given is Δf = 5.5 x 10^{11} Hertz.

To learn more about vibrational-rotational spectrum, visit the link below-

brainly.com/question/18403840

#SPJ4

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Consider a air-filled parallel-plate capacitor with plates of length 8 cm, width 5.52 cm, spaced a distance 1.99 cm apart. Now i
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Answer:

The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

Explanation:

Given that,

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Using formula of capacitance

C'=\dfrac{\epsilon_{0}A_{1}}{d}+\dfrac{k\epsilon_{0}A_{2}}{d}

Put the value into the formula

C'=(\dfrac{8.85\times10^{-12}}{1.99\times10^{-2}})((4.4\times5.52)+(3.6\times5.52)2.6)\times10^{-4}

C'=3.37\times10^{-12}

We need to calculate the  ratio of the new potential energy to the potential energy before the insertion of the dielectric

Using formula of energy

\dfrac{E}{E'}=\dfrac{\dfrac{1}{2}CV^2}{\dfrac{1}{2}C'V^2}

Put the value into the formula

\dfrac{E}{E'}=\dfrac{1.96\times10^{-12}}{3.37\times10^{-12}}

\dfrac{E}{E'}=0.58

Hence, The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

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