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3 years ago

What scientist shot alpha particles into gold

2 answers:

8 0

The scientist that shot alpha particles into gold was Earnest Rutherford. He discovered about electrons. Then, later, he tried to prove that atoms had neutrons. This was done with his gold foil experiment. When the atoms were shot and hit the nucleus, they bounced back... that is how he found out that the atoms had a nucleus, also where our nuclear structure of an atom comes from...

Hope this helps;)

laila [671]3 years ago

5 0

The Geiger–Marsden experiment(s) (also called the Rutherford gold foil experiment) were a landmark series of experiments by which scientists discovered that every atom contains a nucleus where its positive charge and most of its mass are concentrated

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The coefficient of cubical expansion of a substance depends upon

zzz [600]

I think that the coefficient of cubical expansion of a substance depends on THE CHANGE IN VOLUME.

Cubical expansion, also known as, volumetric expansion has the following formula:

Δ V = β V₁ ΔT

V₁ = initial volume of the body
ΔT = change in temperature of the body
β = coefficient of volumetric expansion.

β is defined as the increase in volume per unit original volume per Kelvin rise in temperature.

With the above definition, it is safe to assume that the coefficient of cubical expansion of a substance depends on the change in volume, which also changes in response to the change in temperature.

7 0

3 years ago

When monochromatic light shines perpendicularly on a soap film (n = 1.33) with air on each side, the second smallest nonzero fil

Anika [276]

Let us start from considering monochromatic light as an incidence on the film of a thickness t whose material has an index of refraction n determined by their respective properties.

From this point of view part of the light will be reflated and the other will be transmitted to the thin film. That additional distance traveled by the ray that was reflected from the bottom will be twice the thickness of the thin film at the point where the light strikes. Therefore, this relation of phase differences and additional distance can be expressed mathematically as

$2t + \frac{1}{2} \lambda_{film} = (m+\frac{1}{2})\lambda_{film}$

We are given the second smallest nonzero thickness at which destructive interference occurs.

This corresponds to, m = 2, therefore

$2t = 2\lambda_{film}$

$t = \lambda_{film}$

The index of refraction of soap is given, then

$\lambda_{film} = \frac{\lambda_{vacuum}}{n}$

Combining the results of all steps we get

$t = \frac{\lambda_{vacuum}}{n}$

Rearranging, we find

$\lambda_{vacuum} = tn$

$\lambda_{vacuum} = (278)(1.33)$

$\lambda_{vacuum} = 369.74nm$

4 0

3 years ago

1. Give three examples, from the lab, where potential energy was converted to kinetic energy:

Lubov Fominskaja [6]

Answer:

A book on a table before it falls.

A yoyo before it is released.

A raised weight.

Explanation:

These are all examples of potential energy. So I hope you can find something that is comparable from the lab.

3 0

3 years ago

When gasoline is burned in a car engine,_____ energy is converted into _____ energy.

Kisachek [45]

Chemical Energy is converted into Mechanical Energy.

When gasoline is burned in a car engine, chemical energy is converted into mechanical energy.

8 0

3 years ago

Read 2 more answers

An electric motor with a 1200 hp output drives a machine with an efficiency of 60%. What is the energy output of the machine per

kirill [66]

Answer:

536,904 J/s

Explanation:

The energy output from motor is the input energy in the machine.

We know that efficiency is percentage energy ouput to energy input, and expressed as

$n=\frac {E_o}{E_i}$

Where n and E represent efficiency and energy respectively, subscripts o and i represent output and input respectively. Since for the machine we have the input energy then the output will be the product of efficiency and input energy

Energy output=0.6*1200 hp=720 hp

Converting hp to J/s we multiply by 745.7

Energy is 720*745.7=536,904 J/s

4 0

3 years ago