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xxMikexx [17]
3 years ago
15

Consider the following four objects: a hoop, a flat disk, a solid sphere, and a hollow sphere. Each of the objects has mass M an

d radius R. The axis of rotation passes through the center of each object, and is perpendicular to the plane of the hoop and the plane of the flat disk. Which of these objects requires the largest torque to give it the same angular acceleration?
Physics
1 answer:
Mumz [18]3 years ago
4 0

Answer:

The hoop

Explanation:

We need to define the moment of inertia of the different objects, that is,

DISK:

I_{disk} = \frac{1}{2} mR^2

HOOP:

I_{hoop} = mR^2

SOLID SPHERE:

I_{ss} = \frac{2}{5}mR^2

HOLLOW SPHERE

I_{hs} = \frac{2}{3}mR^2

If we have the same acceleration for a Torque applied, then

mR^2>\frac{2}{3}mR^2>\frac{1}{2} mR^2>\frac{2}{5}mR^2

I_{hoop}>I_{hs} >I_{disk}>I_{ss}

The greatest momement of inertia is for the hoop, therefore will require the largest torque to give the same acceleration

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Perform the following mathematical operation and report answer to the correct number of significant figures 143.6 divided by 21.
Svetllana [295]

The answer to the correct number of significant figures is 6.774.

<h3>What is quotient?</h3>

When a number(big) divided smaller number, the answer obtained greater than zero is called a quotient.

Divide 143.6 ÷ 21.2

143.6/21.2 = 1436/212

                  =6.77358

The quotient is rounded to three significant figures after decimal

143.6 ÷ 21.2 = 6.774

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3 years ago
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If it takes 100N to push a 300N object up an incline plane , what was the MA of the ramp
nika2105 [10]
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At the start of a hockey game, the referee drops the puck between two players from opposing teams. Each player wants to push the
spin [16.1K]

Answer:

a) puck is subjected to both the forces of the hockey sticks in a horizontal direction,

b)the puck does not move since the sum of the forces is zero

c) changing the magnitude or direction of its applied force

Explanation:

a) The puck is subjected to both the forces of the hockey sticks in a horizontal direction, these forces are of equal magnitude and opposite direction since the puck is at rest.

In the direction of the y-axis (perpendicular to the ice) you have the weight of the disk and the normal to this weight that are also in equilibrium.

b) the puck does not move since the sum of the forces is zero, which implies that the forces of the hockey sticks are of equal magnitude and opposite direction.

c) the player has several ways to make the puck move

* slightly changing the angle of the club and therefore the direction of the force, in this case the disc comes out in the direction of this component

* inclined the stick slightly so that the force has a vertical component and the puck jumps in this direction

* Increasing the magnitude of the force so that the puck comes out in the opposite direction to the player

* The worst case, decreasing its force to zero and the disk comes out in its direction by the other force that had the same magnitude.

3 0
3 years ago
A uniform solid sphere rolls down an incline. A) What must be the incline angle (deg) if the linear acceleration of the center o
Nonamiya [84]

Answer:

a) θ = 12.12°

b) equal to 0.21g

Explanation:

Solution:-

Declare variables:

- The mass of solid sphere, m

- The inclination angle, θ

- The linear acceleration a down the slope of the solid sphere is a = 0.21g

Where, g: The gravitational acceleration constant.

- The component of weight of solid sphere directed down the slope is given by:

                          Ws = m*g*sin ( θ )

- Apply Newton's second law of motion down the slope, state:

                        F_net = m*a

- The only net force acting on the solid sphere is the Weight. So, the equation of motion in the coordinate axis ( down the slope ).

                        Ws = m*a

                        m*g*sin ( θ ) = m*0.21*g

- Solve for inclination angle ( θ ):

                        sin ( θ ) = 0.21

                        θ = arcsin ( 0.21 )

                        θ = 12.12°

- If a friction-less block of mass ( m ) moves down the same slope then block has weight component down the slope as:

                         Wb = m*g*sin ( θ )

- Apply Newton's second law of motion down the slope, state:

                        F_net = m*a

- The only net force acting on the solid sphere is the Weight. So, the equation of motion in the coordinate axis ( down the slope ).

                        Ws = m*a

                        m*g*sin ( θ ) = m*a

- Solve for linear acceleration ( a ):

                        g*sin ( θ ) = a

                        a = sin ( 12.12 ) * g

                        a = 0.21g

Answer: The acceleration is independent of mass and only depends on the inclination angle θ.

7 0
4 years ago
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