Answer:
Explanation: do y like me yes or no
Yes. Think of block sitting on top of a bigger block. If the bottom block moves, it will drag the top block with it. Since the force of friction on the small block and its displacement are in the same direction, the "work" is positive. The static friction is a passive force, It is not a source of energy; it transmits the force placed on the bottom block. (And the "work" done by the friction on the bottom block is exactly the negative of the work done on the top block.)
Answer:
Global knowledge is information that is widely accepted and been proven as the truth. It is information that may not necessarily have a source because it is common knowledge and not easily attributed to a certain source. Personal ideas are original to the author and may not be widely accepted. It is important to give credit to others by citing their work to acknowledge that this is not your own findings but rather someone else's. It is plagiarism to use someone else's work as your own without giving credit to their work. -W0lf93
Explanation:
hope this helps
Answer
given,
constant speed of cart on right side = 2 m/s
diameter of nozzle = 50 mm = 0.05 m
discharge flow through nozzle = 0.04 m³
One-fourth of the discharge flows down the incline
three-fourths flows up the incline
Power = ?
Normal force i.e. Fn acting on the cart
v is the velocity of jet
Q = A V
v = 20.37 m/s
u be the speed of cart assuming it to be u = 2 m/s
angle angle of inclination be 60°
now,
F n = 2295 N
now force along x direction
Power of the cart
P = F x v
P = 1987.52 x 20.37
P = 40485 watt
P = 40.5 kW
Answer:
10,600 m
Explanation:
Use range equation:
R = v₀² sin(2θ) / g
R = (433.0 m/s)² sin(2 × 64.8°) / (9.8 m/s²)
R = 14,700 m
The range is shortened by 28.1%.
0.719R = 10,600 m
