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Masteriza [31]
3 years ago
7

Microwave ovens emit microwave energy with a wavelength of 12.1 cm. What is the energy of exactly one photon of this microwave r

adiation?
Physics
1 answer:
EastWind [94]3 years ago
3 0

Answer:

1.64\cdot 10^{-24}J

Explanation:

The energy of a photon is given by:

E=\frac{hc}{\lambda}

where

h=6.63\cdot 10^{-34} Js is the Planck constant

c=3\cdot 10^8 m/s is the speed of light

\lambda is the wavelenght of the photon

For the microwave photons in this problem,

\lambda=12.1 cm=0.121 m

so their energy is

E=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{0.121 m}=1.64\cdot 10^{-24}J

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