Solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined if the solution is extra

Question

2 years ago

12

neous or not. The square root of the quantity 4 x minus 3 end quantity equals 5.

2 answers:

anastassius [24] · Answer 1 · 2023-06-27T01:00:56+03:00

<h2>Answer:</h2>

<u>x= 7</u>.

<h2>Step-by-step explanation:</h2>

<h3>1. Write the expression.</h3>

$\sqrt{4x-3}=5$

<h3>2. Take the square root of both sides of the equation.</h3>

$(\sqrt{4x-3})^{2} =5^{2} \\ \\4x-3=25$

<h3>3. Sum 3 to both sides of the equation.</h3>

$4x-3+3=25+3\\ \\4x=28$

<h3>4. Divide by 4 on both sides of the equation.</h3>

$\frac{4x}{4} =\frac{28}{4} \\ \\x=7$

<h3>5. Express your result.</h3>

<u>x= 7</u>.

ki77a [65] · Answer 2 · 2023-06-27T02:51:08+03:00

Answer:

Step-by-step explanation:

At first let's understanding the situation

The square root of the quantity 4 x minus 3 end quantity equals 5.

we have to find the value if x.

<u>Solu</u><u>tion</u><u>:</u><u>-</u>

$\sqrt{(4x-3)}=5$

<em>By</em><em> </em><em>squari</em><em>ng</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em>

${\sqrt{(4x-3)}}^{2}=5^{2}\\\\\\4x-3=25\\\\4x=25+3\\\\4x=28\\\\x=7$