Question

Solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined if the solution is extraneous or not. The square root of the quantity 4 x minus 3 end quantity equals 5.

Answer 1

Answer:

x= 7.

Step-by-step explanation:

1. Write the expression.

$\sqrt{4x-3}=5$

2. Take the square root of both sides of the equation.

$(\sqrt{4x-3})^{2} =5^{2} \\ \\4x-3=25$

3. Sum 3 to both sides of the equation.

$4x-3+3=25+3\\ \\4x=28$

4. Divide by 4 on both sides of the equation.

$\frac{4x}{4} =\frac{28}{4} \\ \\x=7$

5. Express your result.

x= 7.

Answer 2

Answer:

• x=7

Step-by-step explanation:

At first let's understanding the situation

The square root of the quantity 4 x minus 3 end quantity equals 5.

we have to find the value if x.

Solution:-

$\sqrt{(4x-3)}=5$

By squaring on both sides

${\sqrt{(4x-3)}}^{2}=5^{2}\\\\\\4x-3=25\\\\4x=25+3\\\\4x=28\\\\x=7$