Calculate the number of atoms in exactly 3.5 moles of naturally occurring calcium.

1 answer:

4 0

2.11x10^24 Ca atoms

In order to find the amount of atoms we must use Avogadro’s number, 6.022 x 10^23

Since we have moles, 3.5 the equation would look like this

3.5 moles Ca x 6.022x10^23/1 = 2.1077 x 10^24, which we round to 2.11 x 10^24 atoms of Ca

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