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harina [27]
1 year ago
14

2. My bank account contains pesos 3021 and make monthly withdrawals of pesos 78 for 12 months. What is my new bank balance.

Mathematics
1 answer:
Agata [3.3K]1 year ago
4 0

Answer:

ok I will try solve your problem. good luck

Step-by-step explanation:

a. known: Bank balances : 3021 pesos

monthly withdrawals: 78 pesos

months of withdrawal: 12 months

b. asked: new bank balance?

c. equation: New bank balance= bank balance - ( monthly withdrawals X months of withdrawal)

d. New bank balance: 3021- (78x12)

= 3021 - 936

= 2085 pesos

e. my new bank balance is 2085 pesos.

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Plssss help quick i need it for sum important
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(a) The product of (2x-4)\ and\ (3x^2-x+4)  is calculated to be =6x^3-14x^2+12x-16

(b)The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

<u>Step-by-step explanation:</u>

<u>(a)</u>

(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16

b)

(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8

The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

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Answer:

Step-by-step explanation:

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Read 2 more answers
Y = x^2+5x-3<br> y-x=2<br><br> What is the solution of the linear-quadratic system of equations
Sunny_sXe [5.5K]

Answer:

(-5,-3)

(1,3)

Step-by-step explanation:

Solving with substitution

Set both equations to y =  ...

y = x^2 + 5x - 3

----------------

y - x =2

y = x + 2

----------------

Substitute one of the Y's with the other Y = equation.

x + 2 = x ^2 + 5x -3

Set one side to 0

0 = x^2 + 4x -5

x^2 + 4x - 5 = 0

Simplify by factoring

(x-1) (x+5)

Get your X values

x-1 = 0

x = 1

x+5 = 0

x = -5

Plug in each X into one of the equations to get your Y value.

1st X

y = x + 2

y = 1 + 2

y = 3

When X = 1, Y = 3

2nd X

y = x + 2

y = -5 + 2

y = -3

When X = - 5, Y = -3

Your answers are (1,3) and (-5,-3)

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