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Nastasia [14]
2 years ago
13

For a snack, I ate 40 gummy bears. Each gummy bear weighs 3g.

Chemistry
1 answer:
slega [8]2 years ago
4 0

Taking into account the rule of three, you eat 480 kcal.

<h3>Rule of three</h3>

The rule of three is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them.

That is, what is intended with it is to find the fourth term of a proportion knowing the other three.  

If the relationship between the magnitudes is direct, the direct rule of three must be applied as follow, being a, b and c known data and x the variable to be calculated:

a ⇒ b

c ⇒ x

So: x= (c×b)÷ a

<h3>kcal of eaten gummy bears</h3>

To know the mass of eaten gummy bears, the following rule of three applies: if 1 gummy bear weighs 3 g, 40 gummy bears weigh how much mass?

1 gummy bear ⇒ 3 g

40 gummy bears ⇒ x

So: x= (40 gummy bears× 3 g)÷ 1 gummy bear

Solving:

<u><em>x= 120 g</em></u>

If gummy bears are 100% carbohydrates and carbohydrates are 4 kcal/g, the following rule of three applies: If 1 g has 4 kcal, 120 g has how many kcal?

1 g ⇒ 4 kcal

120 g⇒ x

So: x= (120 g× 4 kcal)÷ 1 g

Solving:

<u><em>x= 480 kcal</em></u>

In summary, you eat 480 kcal.

Learn more with this example:

brainly.com/question/12482948

#SPJ1

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A gas with a pressure of 2.25 atm occupies 450.0 mL at a temperature of 300 K. What is the volume at 405.0 K?
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The volume of the gas at a temperature of 405.0 K would be 607.5 mL. Making option D the right answer to the question.

What is the volume of the gas?

To find the volume of the gas, the equation to be used would have to be combine gas law.

Combine gas law as the name suggest uses the combination of Charles law which measures Volume against temperature, and Gay-Lussac's law which measures Pressure/Temperature, and Boyle's law  which measures pressure X volume where k is constant.

Using the combine law to find the volume, we have:

P₁V₁/T₁=P₂V₂/T₂

Where P₁ = initial pressure

           V₁ = initial volume

             T₁ = initial temperature

            P₂ = final  pressure

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            T₂ = final  temperature

P₁ = 2.25atm

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V₂ = ?

D) 607.5 mL

= [2.25(450)]÷300=[2.25(V₂]÷405

Making  V₂ the subject

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V₂ = 607.5 mL

In summary, a gas with an initial pressure of 2.25atm, an initial pressure of 450.0 mL and an initial temperature of 300 K would have a final volume of 607.5 mL if the temperature is increased to  405.0 K.

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HEY DEAR..

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HOPE ITS HELPFULLL

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Explanation:

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