Question

A gas with a pressure of 2.25 atm occupies 450.0 mL at a temperature of 300 K. What is the volume at 405.0 K?

Answer 1

The volume of the gas at a temperature of 405.0 K would be 607.5 mL. Making option D the right answer to the question.

What is the volume of the gas?

To find the volume of the gas, the equation to be used would have to be combine gas law.

Combine gas law as the name suggest uses the combination of Charles law which measures Volume against temperature, and Gay-Lussac's law which measures Pressure/Temperature, and Boyle's law  which measures pressure X volume where k is constant.

Using the combine law to find the volume, we have:

P₁V₁/T₁=P₂V₂/T₂

Where P₁ = initial pressure

           V₁ = initial volume

             T₁ = initial temperature

            P₂ = final  pressure

            V₂ = final  volume

            T₂ = final  temperature

P₁ = 2.25atm

V₁ = 450.0 mL

T₁ = 300 K

T₂ = 405.0 K

V₂ = ?

D) 607.5 mL

= [2.25(450)]÷300=[2.25(V₂]÷405

Making  V₂ the subject

 3.375=2.25 V₂ ÷ 405

V₂ = 3.375 x 405 ÷ 2.25

V₂ = 607.5 mL

In summary, a gas with an initial pressure of 2.25atm, an initial pressure of 450.0 mL and an initial temperature of 300 K would have a final volume of 607.5 mL if the temperature is increased to  405.0 K.

Learn more about Combine gas law here: brainly.com/question/13538773

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