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alekssr [168]
2 years ago
14

The growth of the plants that the animal used for food could not keep up with the needs of the population. there was so little f

ood for the animals, the population declined. how does this relate to carrying capacity?
it does not relate to carrying capacity.



the number of animals greatly exceeded the carrying capacity, which didn't destroy the food source and caused a population increase



the number of animals was lower than the carrying capacity, which didn't destroy the food source and caused a population increase.



the number of animals greatly exceeded the carrying capacity, destroying the food sources and causing the population to decline.
Chemistry
1 answer:
WARRIOR [948]2 years ago
8 0

In this case, the population has exceeded the available food, thus causing a decline in the population.

<h3>What is carrying capacity?</h3>

It is the maximum population size that an ecosystem can sustain based on the resources that it has.

Above the carrying capacity, resources become extremely limited and competition becomes stiff in the population. Thus, the population declines.

Below the carrying capacity, resources are abundant and the population grows. Most of the time, a mature population hovers around the carrying capacity of the ecosystem.  

More on carrying capacity can be found here: brainly.com/question/797991

#SPJ1

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Given the following, determine ΔG°f at 298 K for SnO. Sn(s) + SnO2(s) → 2SnO(s) ; ΔG° = 12.0 kJ at 298K
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Answer:

The value of change in Gibbs free energy for tin(II) oxide solid is -251.9 kJ/mol.

Explanation:

Sn(s) + SnO_2(s)\rightarrow 2SnO(s), \Delta G_{f}^{o} = 12.0 kJ

\Delta G_{f,SnO_2}^{o}= -515.8kJ/mol

\Delta G_{f,Sn}^{o}= 0 kJ/mol

\Delta G_{f,SnO}^{o}=?

\Delta G_{f}^{o}=\sum ((\Delta G_{f}^{o})_ {products})-\sum ((\Delta G_{f}^{o})_ {reactants})

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\Delta G_{f,SnO}^{o}=-251.9 kJ/mol

The value of change in Gibbs free energy for tin(II) oxide solid is -251.9 kJ/mol.

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