The third question requires you to solve for the weight of sodium (Na) and weight of Chloride (Cl) from the calculated moles of each element Na, and Cl.
So, you need to multiply the calculated moles of Na with its molar mass (23 g/ mol) to get the answer for Na. And multiply the calculated moles of Cl with its molar mass (35.45 g/mol) to get the answer for Cl.
Answer:
the atomic number decreased in 2, from 100 to 100 - 2 = 98. 3) Hence the formed atom has atomic number 98, which is californium, Cf, and the isotope is californium - 253. 4) The item that completes the given alpha decay reaction is: ₉₈²⁵³ Cf.
Explanation:
Answer: There will be 0.00002 meq per Liter of the solution.
Explanation:
Normality is defined as the umber of gram equivalents dissolved per liter of the solution.
Equivalent weight is calculated by dividing the molecular weight by n factor.
n= charge for charged species , For
, n =2
Thus there will be 0.00002 meq per Liter of the solution.