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Sedaia [141]
2 years ago
7

How many moles are in 1.52908x1024 molecules of Potassium phosphate (K3(PO4))?

Chemistry
1 answer:
lara31 [8.8K]2 years ago
4 0

Answer:

<h2>2.54 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{1.52908 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\

We have the final answer as

<h3>2.54 moles</h3>

Hope this helps you

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Answer:- 0.143 M

Solution:- HCl and NaOH reacts in 1:1 mol ratio as shown in the below reaction:

HCl(aq)+NaOH(aq)\rightleftharpoons NaCl(aq)+H_2O(l)

Let's calculate the initial moles of HCl and the moles of NaOH added to it:

250.mL(\frac{1L}{1000mL})(\frac{0.3molHCl}{1L})

= 0.075 mol HCl

100.mL(\frac{1L}{1000mL})(\frac{0.25molNaOH}{1L})

= 0.025 mol NaOH

Since they react in 1:1 mol ratio, 0.025 mol of NaOH will react with 0.025 moles of HCl.

Remaining moles of HCl = 0.075 - 0.025 = 0.050

Total volume of the solution = 0.250 L + 0.100 L = 0.350 L

So, the concentration of HCl in the resulting solution = \frac{0.050mol}{0.350L}

= 0.143 M

Hence, the concentration of HCl acid in the resulting solution is 0.143 M.

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List a possible set of four quantum numbers (n,l,ml,ms) in order, for the highest energy electron in gallium?
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Can someone help me with this molar mass problem?[It’s the last one]
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Answer:

54.18 \times 10^{23} \ moles in 3 mole of  Al_2(SO_4)_3

Explanation:

It is clear that in the given 1\ mole of Al_2(SO_4)_3 have 3\ ions of SO_4^2^-

Therefore 3 moles of Al_2(SO_4)_3 will have 3\times3=9 \ ions of   SO_4^2^-

Since 1 ion of anything is equivalent to 6.02\times10^{23} \ moles

Therefore 3 moles of Al_2(SO_4)_3 will have 3\times3=9 \ ions of   SO_4^2^-

Which is equivalent to 9 \times6.02\times10^{23}=54.18\times10^{23} \ moles

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