How many moles are in 1.52908x1024 molecules of Potassium phosphate (K3(PO4))?
1 answer:
Answer:
<h2>2.54 moles</h2>Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>2.54 moles</h3>Hope this helps you
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Answer:
a)
The overall balanced combustion reaction is written as :
b)
the higher heating values per unit mass of LPG = 49.9876 MJ/kg
the lower heating values per unit mass of LPG = 46.4933 MJ/kg
Explanation:
a)
The stoichiometric equation can be expressed as :
Now, equating the coefficient of carbon; we have:
(0.7×3)+(0.05×4)+(0.25×3) = a
a = 3.05
Also, Equating the coefficient of hydrogen : we have:
(0.7 × 8) +(0.05 × 10) + ( 0.25 × 6) = 2 b
2b = 7.6
b = 3.8
Equating the coefficient of oxygen
2x = 2a + b
Equating the coefficient of Nitrogen
Therefore, The overall balanced combustion reaction can now be written as :
Now; To determine the stoichiometric F/A and A/F ratios; we have:
b)
What are the higher and lower heating values per unit mass of LPG?
Let calculate the molecular mass of the fuel in order to determine their mass fraction of the fuel components.
Molecular mass of the fuel
= 30.8 + 2.9 + 10.5
= 44.2 kg/mol
Mass fraction of the fuel components can now be calculated as :
Finally; calculating the higher heating values per unit mass of LPG; we have:
calculating the lower heating values per unit mass of LPG; we have: