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Sedaia [141]
3 years ago
7

How many moles are in 1.52908x1024 molecules of Potassium phosphate (K3(PO4))?

Chemistry
1 answer:
lara31 [8.8K]3 years ago
4 0

Answer:

<h2>2.54 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{1.52908 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\

We have the final answer as

<h3>2.54 moles</h3>

Hope this helps you

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3 years ago
How is the molar heat of sublimation related to the molar heats of vaporization and fusion? On what law are these relationships
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Answer: Hsub=Hfus+Hvap

Explanation:

The molar heat of vaporization measured in kilojoules per mole, or kJ/mol is the energy needed to make vapor one mole of a liquid. .

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the molar heat of fusion measured in kilojoules per mole, or kJ/mol is the energy needed to melt one mole of a solid.

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3 years ago
The titration of Na2CO3 with HCl has the following qualitative profile: a. Identify the major species in solution at points A-F.
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Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.

a) We need to find the major species from A to F.

Major Species at A:

1. Na_{2} CO_{3}

Major Species at B:

1. Na_{2} CO_{3}

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Major Species at C:

1. NaHCO_{3}

Major Species at D:

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Major Species at E:

1. H_{2}CO_{3}

Major Species at F:

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pH = pKa_{1} = 6.35

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At point D,

pH = pKa_{2} + log [HCO_{3}.^{-1}]/[H2CO_{3}]

pH = pKa_{2} = 10.33

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