Question

How many moles are in 1.52908x1024 molecules of Potassium phosphate (K3(PO4))?

Answer 1

Answer:

2.54 moles

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L}$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{1.52908 \times {10}^{24} }{6.02 \times {10}^{23} }$

We have the final answer as

2.54 moles

Hope this helps you