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Dennis_Churaev [7]
2 years ago
10

Find the frequency of a tuning fork that takes2.50×10−3s to complete one oscillation.

Physics
1 answer:
maksim [4K]2 years ago
6 0

The frequency of a tuning fork that takes2.50×10⁻³ s to complete one oscillation would be 400 Hz.

<h3>What is the frequency?</h3>

It can be defined as the number of cycles completed per second. It is represented in hertz and inversely proportional to the wavelength.

As given in the problem a tuning fork takes 2.50×10⁻³ s to complete one oscillation.

Frequency = 1/time period of the oscillation

Frequency of the tuning fork = 1/time period

                                                   =1/2.50×10⁻³

                                                   =400 Hz

Thus the frequency of a tuning fork comes out to be 400 Hz.

Learn more about frequency here, refer to the link;

brainly.com/question/14316711

#SPJ1

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Answer:

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The vertex is at 2 seconds.  The height of the stone at this time is:

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We know that for sample A, we have n moles, a temperature T and a volume V, then the pressure of this sample will be:

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n/2 moles, temperature T/2 and a volume V/2, then the pressure will be:

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Then the correct option is e.

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