In addition to acceleration of gravity we experience centrifugal acceleration away from the axis of rotation of the earth. this additional acceleration has value ac = r w^2 where w = angular velocity and r is distance from your spot on earth to the earth's axis of rotation so r = R cos(l) where l = 60 deg is the lattitude and R the earth's radius and w = 1 / (24hr x 3600sec/hr)
now you look up R and calculate ac then you combine the centrifugal acc. vector ac with the gravitational acceleration vector ag = G Me/R^2 to get effective ag' = ag -

5 0

2 years ago

What is the difference between mutual flux, leakage flux and magnetizing flux

Lemur [1.5K]

In simple words, flux can be stated as the rate of flow of a fluid, radiant energy, or particles across a given area.

Explanation:

Mutual Flux:

The magnetic lines present in among two magnets or solenoid is mutual flux.
These are the lines in which the attraction and repulsion happens.
The SI unit of mutual flux is the Henry

Leakage Flux:

In simple words, it can be stated as the magnetic flux which does not follow the specially designed way in a magnetic circuit.
Leakage flux in the induction motor takes spot due to current runs through the essence of the induction motor.
The SI unit of Leakage flux is the Weber

Magnetizing flux

Magnetic flux is an analysis of the entire magnetic field which moves in a given field
In simple words can be defined as the Magnetic flux is what generates the field around a magnetic material.

The SI unit of magnetic flux is the Weber

3 0

2 years ago

Singly charged uranium-238 ions are accelerated through a potential difference of 2.20 kV and enter a uniform magnetic field of

Aleonysh [2.5K]

Answer:

r = 0.0548 m

Explanation:

Given that,

Singly charged uranium-238 ions are accelerated through a potential difference of 2.20 kV and enter a uniform magnetic field of 1.90 T directed perpendicular to their velocities.

We need to find the radius of their circular path. The formula for the radius of path is given by :

$r=\dfrac{1}{B}\sqrt{\dfrac{2mV}{q}}$

m is mass of Singly charged uranium-238 ion, $m=3.95\times 10^{-25}\ kg$

q is charge

So,

$r=\dfrac{1}{1.9}\times \sqrt{\dfrac{2\times 3.95\times 10^{-25}\times 2.2\times 10^3}{1.6\times 10^{-19}}}\\\\r=0.0548\ m$

So, the radius of their circular path is equal to 0.0548 m.

4 0

2 years ago