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2 years ago

Write a balanced equation for the formation from its elements of sodium peroxide, an industrial bleach.

Chemistry

1 answer:

Kipish [7]2 years ago

6 0

The answer is- The balanced equation is $2Na + O_2$ → $Na_2O_2$ .

A balanced chemical equation is the one in which there is same number of each types of atoms on both the reactant and product side.

An unbalanced chemical reaction violates which law?

To balance the equation, we keep the count of the elements balanced on both sides of the reaction which maintains the same total mass of elements on both sides.
Thus, if an equation is not balanced, then it violates the law of conservation of mass.

Now, the chemical formula of sodium peroxide (industrial bleach) is $Na_2O_2$ . Thus, its constituent elements are sodium ( $Na$ ) and oxygen ( $O$ ).
Therefore, the chemical equation is - $Na +O_2$ → $Na_2O_2$
But the above equation is not balanced as the number of $Na$ atoms is not same on both sides of the arrow. To balance this, coefficient 2 is added in front of $Na$ .
Hence, the balanced equation is $2Na + O_2$ → $Na_2O_2$ .

To learn more about the balanced equation, visit:

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2 years ago

Read 2 more answers

2. Consider the reaction 2NO(g) + O2(g) → 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is r

vredina [299]

Answer :

(a) The rate of $NO_2$ formed is, 0.066 M/s

(b) The rate of $O_2$ formed is, 0.033 M/s

Explanation : Given,

$\frac{d[NO]}{dt}$ = 0.066 M/s

The balanced chemical reaction is,

$2NO(g)+O_2(g)\rightarrow 2NO_2(g)$

The rate of disappearance of $NO$ = $-\frac{1}{2}\frac{d[NO]}{dt}$

The rate of disappearance of $O_2$ = $-\frac{d[O_2]}{dt}$

The rate of formation of $NO_2$ = $\frac{1}{2}\frac{d[NO_2]}{dt}$

As we know that,

$\frac{d[NO]}{dt}$ = 0.066 M/s

(a) Now we have to determine the rate of $NO_2$ formed.

$\frac{1}{2}\frac{d[NO_2]}{dt}=\frac{1}{2}\frac{d[NO]}{dt}$

$\frac{d[NO_2]}{dt}=\frac{d[NO]}{dt}=0.066M/s$

The rate of $NO_2$ formed is, 0.066 M/s

(b) Now we have to determine the rate of molecular oxygen reacting.

$-\frac{d[O_2]}{dt}=-\frac{1}{2}\frac{d[NO]}{dt}$

$\frac{d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s$

The rate of $O_2$ formed is, 0.033 M/s

6 0

3 years ago

The concentration of protein in a urine sample is calculated to be 2.77 μg/mL. What is the concentration of this solution in uni

maxonik [38]

Answer:

The concentration of this solution in units of pounds per gallon is $2.776*10^{-5} \frac{lb}{gal}$

Explanation:

Units of measurement are established models for measuring different quantities. The conversion of units is the transformation of a quantity, expressed in a certain unit of measure, into an equivalent one, which may or may not be of the same system of units.

In this case, the conversion of units is carried out knowing that 1 μg are equal to 2.205*10⁻⁹ Lb and 1 mL equals 0.00022 Gallons. So

$2.77 \frac{ug}{mL} = \frac{2.77 ug}{mL}$

If 1 μg equals 2.205*10⁻⁹ lb, 2.77 μg how many lb equals?

$lb=\frac{2.77ug*2.205*10^{-9}lb }{1ug}$

lb=6.10785*10⁻⁹

So, 2.77 μg= 6.10785*10⁻⁹ lb

Then:

$2.77 \frac{ug}{mL} = \frac{2.77 ug}{mL}=\frac{6.10785*10^{-9}lb }{mL} =\frac{6.10785*10^{-9}lb }{0.00022 gal} =\frac{6.10785*10^{-9}lb }{0.00022 gal}$

You get:

$2.77 \frac{ug}{mL} = 2.776*10^{-5} \frac{lb}{gal}$

The concentration of this solution in units of pounds per gallon is $2.776*10^{-5} \frac{lb}{gal}$

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3 years ago

Arrange the following compounds in order of increasing acidity, and explain the reasons for your choice of order. Enter your ans

NNADVOKAT [17]

Answer:

(a) > (d) > (c) > (b)

Explanation:

Acidic character is based upon inductive effect of the functional group that are attached to parent chain.

1. Nitro is a -I group which makes phenol acidic due to increased resonance, 2. bromine is a -I group but it is weaker than nitro group

3. phenol is more acidic than cyclohexanol due to resonance stabilization of resonance and among halogen F>Cl>Br>I is the order of acidity

4. cyclohexanol will be weakest as it is not associated with any -I groups here.

so the order of acidity will be

(a). 4-nitropheno > (d). 4-bromophenol > (c). 2,6-difluorocyclohexanol > (b). cyclohexanol

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3 years ago