I have attached all the problems, but really if you just do one so I understand how to do it, that would be great!
1 answer:
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448 K is the final temperature of the water.
<h3>What is specific heat capacity?</h3>The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).
Given,
the mass of Na is 23 g
The volume of water = 293 cm3
Mass of water = 293 g
Total solution mass = 23 g + 293 g = 316 g
Specific heat capacity of water = 4.18 J/Kg
The equation relating mass, heat, specific heat capacity and temperature change is:
q = mcΔT
197 kJ = 316 g x 4.18 J/Kg x ()
197 kJ = 316 g x 4.18 J/Kg x ( -298 K)
0.1491429956 x 1000 = -298 K
149.1429956 + 298 =
447.1429956 =
448 K =
Hence, 448 K is the final temperature of the water.
<h3>What does a high specific heat capacity mean?</h3>A high specific heat capacity means that it can store a large amount of thermal energy for a small change in mass or temperature.
Learn more about specific heat capacity here:
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