if 3.26 g is dissolved in enough water to make exactly 323 ml of solution, what is the molar cocentration of nitrate ion g

Which of the following molecules would one expect to have a non-polar covalent bond?

Ivahew [28]

b. F₂ have a polar covalent bond

Explanation:

The type of bond depends on the difference of the electronegativity of the two elements.

if the electronegativity difference is under 0.4 the bond is non-polar covalent

if the electronegativity difference is between 0.4 and 1.7 the bond is polar covalent

if the electronegativity difference is greater 1.7 the bond is ionic

a. HCl

electronegativity of Cl - electronegativity of H = 3 - 2.2 = 0.8, so the bond is polar covalent

b. F₂

electronegativity of F - electronegativity of F = 4 - 4 = 0 , so the bond is non-polar covalent

c. HF

electronegativity of F - electronegativity of H = 4 - 2.2 = 1.8, in this case because non-metals are involved in the bond we consider this to be a polar covalent bond.

d. ClF

electronegativity of F - electronegativity of Cl = 4 - 3 = 1, so the bond is polar covalent

Learn more about:

type of chemical bonds

brainly.com/question/13178368

brainly.com/question/2344549

#learnwithBrainly

7 0

3 years ago

A 13.5g sample of gold is heated, then placed in a calorimeter containing 60g of water. The temperature of water increases from

sweet-ann [11.9K]

Answer:

$T_i~=163.1$ ºC

Explanation:

We have to start with the variables of the problem:

Mass of water = 60 g

Mass of gold = 13.5 g

Initial temperature of water= 19 ºC

Final temperature of water= 20 ºC

Initial temperature of gold= Unknow

Final temperature of gold= 20 ºC

Specific heat of gold = 0.13J/gºC

Specific heat of water = 4.186 J/g°C

Now if we remember the heat equation:

$Q_H_2_O=m_H_2_O*Cp_H_2_O*deltaT$

$Q_A_u=m_A_u*Cp_A_u*deltaT$

We can relate these equations if we take into account that all heat of gold is transfer to the water, so:

$m_H_2_O*Cp_H_2_O*deltaT=~-~m_A_u*Cp_A_u*deltaT$

Now we can put the values into the equation:

$60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C=-(13.5~g*0.13~J/g{\circ}C*(20-T_i)~{\circ}C)$

Now we can solve for the initial temperature of gold, so:

$T_i~=(\frac{60~g*4.186~J/g{\circ}C*(20-19)~{\circ}C}{13.5~g*0.13~J/g{\circ}C})+20$

$T_i~=163.1$ ºC

I hope it helps!

5 0

3 years ago

V2O5 + Ca = V + CaO balance the eqaution

andreyandreev [35.5K]

Answer: The balanced equation is $V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO$ .

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, $V_{2}O_{5} + Ca \rightarrow V + CaO$

Here, number of atoms on reactant side are as follows.

V = 2
O = 5
Ca = 1

The number of atoms on product side are as follows.

V = 1
O = 1
Ca = 1

In order to balance this equation, multiply Ca by 5 on reactant side. Multiply V by 2 and CaO by 5 on product side. Therefore, the equation can be rewritten as follows.

$V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO$

Now here, number of atoms on reactant side are as follows.

V = 2
O = 5
Ca = 5

The number of atoms on product side are as follows.

V = 2
O = 5
Ca = 5

Since, there are same number of atoms on both reactant and product side. So, the equation is now balanced.

Thus, we can conclude that the balanced equation is $V_{2}O_{5} + 5Ca \rightarrow 2V + 5CaO$ .

5 0

3 years ago

How many moles are in 28g of Fe2O3

nlexa [21]

Find the molar mass of Fe_2O_3

2Fe = 2*56 = 112

3O = 3* 16 = 48

Molar Mass = 160 grams

moles= given mass / molar mass

moles = 28 / 160

moles = 0.175 <<<< answer

6 0

3 years ago

Atomic number indicates which of the following

Furkat [3]

The atomic number of an element gives the element it's identity. This is also known as the number of protons within an element. If you have the number of protons but don't know the element's atomic mass, add the protons and neutrons to get the mass number.
I hope this helped!

8 0

4 years ago