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devlian [24]
3 years ago
6

How many grams of water will I obtain from the combustion of 0.9249 mol of pentane (C5H12) in the following reaction?

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
8 0

Answer:

Mass = 2.7 g

Explanation:

Given data:

Number of moles of C₅H₁₂ = 0.9249 mol

Mass of water = ?

Solution:

Chemical equation:

C₅H₁₂ + 8O₂     →     5CO₂ + 6H₂O

Now we will compare the moles of water with pentane.

                 C₅H₁₂       :         H₂O

                    1            :           6

                0.9249     :          1/6×0.9249= 0.15 mol

Mass of water:

Mass = number of moles × molar mass

Mass = 0.15 mol × 18 g/mol

Mass = 2.7 g

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The density of ethanol, a colorless liquid that is commonly known as grain alcohol, is 0.798 g/mL Calculate the mass of 205 mL o
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4 0
1 year ago
A drum used to transport crude oil has a volume of 162 L. How many grams of water, as steam, are required to fill the drum at 1.
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Answer:

114.48g

Explanation:

Step 1:

Data obtained from the question:

Volume (V) = 162 L

Pressure (P) = 1.20 atm

Temperature = 100°C = 100°C+ 273 = 373K

Number of mole (n) of H2O =?

Recall:

Gas constant (R) = 0.082atm.L/Kmol

Step 2:

Determination of the number of mole of H2O i.e steam.

Using the ideal gas equation, the number of mole of H2O can be obtained as follow:

PV = nRT

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Divide both side by 0.082 x 373

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Step 3:

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This is illustrated below:

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