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3 years ago

How many grams of water will I obtain from the combustion of 0.9249 mol of pentane (C5H12) in the following reaction?

Chemistry

1 answer:

NNADVOKAT [17]3 years ago

8 0

Answer:

Mass = 2.7 g

Explanation:

Given data:

Number of moles of C₅H₁₂ = 0.9249 mol

Mass of water = ?

Solution:

Chemical equation:

C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O

Now we will compare the moles of water with pentane.

C₅H₁₂ : H₂O

1 : 6

0.9249 : 1/6×0.9249= 0.15 mol

Mass of water:

Mass = number of moles × molar mass

Mass = 0.15 mol × 18 g/mol

Mass = 2.7 g

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2 years ago

Explain the difference between cocl2 6h2o and anhydrous cobalt chloride

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4 years ago

The density of ethanol, a colorless liquid that is commonly known as grain alcohol, is 0.798 g/mL Calculate the mass of 205 mL o

katovenus [111]

Answer:

Mass of 205 mL of the liquid is 164 g

Explanation:

We know, $density=\frac{mass}{volume}$

Here density of liquid is 0.798 g/mL and volume of liquid is 205 mL

So, mass of liquid = $density\times volume$

= $(0.798 g/mL)\times (205 mL)$

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4 years ago

Balance each reaction and write its reaction quotient, Qc:(b) POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Komok [63]

When we balance the given equation

POCl₃(g) ⇄ PCl₃(g) + O₂(g)

We will get

2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

Solution:

Balancing the given equation

POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Balancing the number of O

2POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Balancing the number of P and Cl

2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

We get the balanced equation

2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

The reaction quotient will be

Qc = [product] / [reactant]

Qc = [PCl₃(g) + O₂(g)] / [POCl₃(g) ]

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1 year ago

A drum used to transport crude oil has a volume of 162 L. How many grams of water, as steam, are required to fill the drum at 1.

Paraphin [41]

Answer:

114.48g

Explanation:

Step 1:

Data obtained from the question:

Volume (V) = 162 L

Pressure (P) = 1.20 atm

Temperature = 100°C = 100°C+ 273 = 373K

Number of mole (n) of H2O =?

Recall:

Gas constant (R) = 0.082atm.L/Kmol

Step 2:

Determination of the number of mole of H2O i.e steam.

Using the ideal gas equation, the number of mole of H2O can be obtained as follow:

PV = nRT

1.2x 162 = n x 0.082 x 373

Divide both side by 0.082 x 373

n = (1.2x 162) /(0.082 x 373)

n = 6.36 moles

Step 3:

Determination of mass of H2O i.e steam:

This is illustrated below:

Molar Mass of H2O = (2x1) + 16 = 2 + 16 = 18g/mol

Number of mole H2O = 6.36 moles

Mass of H2O =?

Mass = number of mole x molar Mass

Mass of H2O = 6.36 x 18

Mass of H2O = 114.48g

Therefore, the mass of H2O i.e steam required to fill the drum of crude oil is 114.48g

7 0

3 years ago