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Agata [3.3K]
3 years ago
11

What prevents the expression of a recessive allele

Chemistry
2 answers:
Nikolay [14]3 years ago
7 0
Usually the presence of a dominant version of allele masks the expression of a recessive allele. A recessive allele is only phenotype is only expressed when 2 recessive alleles combine. 
astra-53 [7]3 years ago
3 0
Dominant alleles prevent the expression of a recessive allele, unless it is a genotype of two recessive alleles.
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Using the information in the table, calculate the number of moles in a \pu{7.89 kg}7.89 kg7, point, 89, space, k, g sample of as
Karolina [17]

We have to find the number of moles in a 7.89 kg sample of aspirin.

The formula of aspirin is: C₉H₈O₄

We are given the molar mass of C, H and O:

H: 1.008 g/mol C: 12.01 g/mol O: 16.00 g/mol

Since one molecule of aspirin has 9 atoms of C, 8 atoms of H and 4 atoms of O, and using the molar masses given, we can calculate the molar mass of aspirin:

molar mass of aspirin = 9 * 12.01 g/mol + 8 * 1.008 g/mol + 4 * 16.00 g/mol

molar mass of aspirin = 180.154 g/mol

Before we find the number of moles we can convert 7.89 kg to g. Since we know that there are 1000 g in 1 kg, we can convert it like this:

1000 g = 1 kg

mass of sample = 7.89 kg * 1000 g/1 kg

mass of sample = 7890 g

Finally, we can find the number of moles in the sample using the molar mass.

number of moles = 7890 g * 1 mol/180.154 g

number of moles = 43.795 moles

Answer: The number of moles in the sample is 43.8 moles (using 3 SF)

7 0
1 year ago
Compare amplitudes, wavelengths, and frequencies of waves
mr_godi [17]

Answer:

The answer is option b.

Explanation:

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2 years ago
Which of the following measurements is expressed to three significant figures?
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Which of the following measurements is expressed to three significant figures?
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3 years ago
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Based on the equation, how many grams of Br2 are required to react completely with 36.2 grams of AlCl3?
s2008m [1.1K]

Answer:

65.08 g.

Explanation:

  • For the reaction, the balanced equation is:

<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>

2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.

  • Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:

<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>

<u><em>Using cross multiplication:</em></u>

2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.

0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.

∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃  = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.

<em>∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass</em> = (0.4072 mol)(159.808 g/mol ) = <em>65.08 g.</em>

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For "gas in liquid solution", which of the following will act as a solute?
svlad2 [7]

Answer:gas

Explanation:ck12

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