You find the x coordinates using x = -b/2a = -6/2(-1) = 3
Substitute 3 in the equation and find y
y = -(3^2) + 6(3) - 12 = -9 + 18 - 12 = -3
Vertex (3,-3)
Answer:
The answer is 8 : 22, 12:33 as they are two equelivant ratios 11 and 4
The less coefficient in front of x^2, the wider graph
the smallest coefficient is 1/5 , so the widest graph is y=(1/5)x²
3x-4y=10
-20-x+2y=10 then -30+2y=x now plug this in the other equation:
3(-30+2y)-4y=10
-90+6y-4y=10
2y=100
y=50
Answer:
Solution given:
f(x) = x +1 and g(x) = x²,
now
(gºf)(x) =g(fx)=g(x+1)=(x+1)²
<u>D) (gºf)(x) = (x + 1)^2</u>
